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Tresset [83]
3 years ago
11

Given that x overbarequals3.6667​, s Subscript xequals2.0656​, y overbarequals4.2167​, s Subscript yequals1.5613​, and requalsne

gative 0.9344​, determine the​ least-squares regression line.
Mathematics
1 answer:
Shtirlitz [24]3 years ago
6 0

Answer:

y = 0.7063x+2.7790

Step-by-step explanation:

Given that

x bar = 3.6667\\s_x= 2.0656\\y bar = 4.2167\\s_7 = 1.5613\\r = -0.9344

We have slope of linear regression line is

a=r*\frac{s_y}{s_x} =0.9344(\frac{1.5613}{2.0656} )\\=0.7063

So regression line would be of the form

y-4.2167 = 0.7063(x-2.0656) (since it passes through xbar, y bar)

y = 0.7063x+2.7790

is the equation of regression line.

You might be interested in
The area of a circle is 43.25cm2.<br> Find the length of the radius rounded to 2 DP.
Monica [59]

Answer:

3.71 cm

Step-by-step explanation:

Hi there!

Area of a circle equation: A=\pi r^2 where r is the radius

Plug in the area 43.25 cm²

43.25=\pi r^2

Divide both sides by π to isolate r²

\frac{43.25}{\pi} =\frac{\pi r^2}{\pi} \\\frac{43.25}{\pi}=r^2

Take the square root of both sides to isolate r

\sqrt{\frac{43.25}{\pi}} =r\\3.71=r

Therefore, the length of the radius rounded to 2 decimal points is 3.71 cm.

I hope this helps!

8 0
3 years ago
Which equation has the solutions x = -3 ± √3i/2 ?
Maurinko [17]

Answer:Answer is option C : [x^{2} + 3x + 3 ] =0

Note:  None of options matches with given question.

instead of "-3" , there should be "-\frac{3}{2}".

Step-by-step explanation:

Note:  None of options matches with given question.

instead of "-3" , there should be "\frac{3}{2}".  

Here, First thing you have to observe the nature of roots.

∴ x = -\frac{3}{2}+\frac{\sqrt{3}}{2}i and x = -\frac{3}{2}-\frac{\sqrt{3}}{2}

∴ [ x+(\frac{3}{2}-\frac{\sqrt{3}}{2}i) ][ x+(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ]=0

∴ [ x^{2} + x(\frac{3}{2}+\frac{\sqrt{3}}{2}i)+ x(\frac{3}{2}-\frac{\sqrt{3}}{2}i) + (\frac{3}{2}-\frac{\sqrt{3}}{2}i)(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ]=0

∴ [x^{2} + \frac{3}{2}x + \frac{\sqrt{3}}{2}ix + \frac{3}{2}x - \frac{\sqrt{3}}{2}ix + (3-\frac{\sqrt{3}}{2}i)(3+\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + (\frac{3}{2}-\frac{\sqrt{3}}{2}i)(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + \frac{9}{4} - (\frac{\sqrt{3}}{2}i)(\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + \frac{9}{4} - (\frac{3}{4}) i^{2} ] =0

∴ [x^{2} + 3x + \frac{9}{4} + (\frac{3}{4}) ] =0

∴ [x^{2} + 3x + \frac{12}{4} ] =0  

∴ [x^{2} + 3x + 3 ] =0  

Thus, Answer is option C : <em>[x^{2} + 3x + 3 ] =0  </em>

6 0
3 years ago
I was wondering if someone could explain this in another way *you might have to click on the post to view the picture*
Shtirlitz [24]
Look on google and look on others websites and you will find a lot of answers hope this helps
7 0
3 years ago
I need help with the cross canceling
mihalych1998 [28]

Answer:58

Step-by-step explanation:

20×4 then 2×7 then add both answers u get 58

8 0
3 years ago
Read 2 more answers
Please help me figure this out​
polet [3.4K]

Answer:3⁴ and 81¹

Step-by-step explanation:

3⁹= 19683

3⁴= 81

-9²= -81

9⁹= 387,420,489

81¹= 81

8 0
3 years ago
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