Ask question

Ask question

All categories

3 years ago

11

Given that x overbarequals3.6667, s Subscript xequals2.0656, y overbarequals4.2167, s Subscript yequals1.5613, and requalsne

gative 0.9344, determine the least-squares regression line.

1 answer:

Shtirlitz [24]3 years ago

6 0

Answer:

$y = 0.7063x+2.7790$

Step-by-step explanation:

Given that

$x bar = 3.6667\\s_x= 2.0656\\y bar = 4.2167\\s_7 = 1.5613\\r = -0.9344$

We have slope of linear regression line is

$a=r*\frac{s_y}{s_x} =0.9344(\frac{1.5613}{2.0656} )\\=0.7063$

So regression line would be of the form

$y-4.2167 = 0.7063(x-2.0656)$ (since it passes through xbar, y bar)

$y = 0.7063x+2.7790$

is the equation of regression line.

You might be interested in

you are selling pandesal to raise money for a school field trip. Pandesal with cheese cost 8.00 pesos and ube pandesal cost 9.00

Lera25 [3.4K]

Answer:

Let's define:

C = number of pandesal with cheese that you sell

U = number of pandesal with ube that you sell.

If you sell these numbers of each, the total profit you get is:

C*8.00 pesos + U*9.00 pesos.

And yo want to get at least 180 pesos, then:

C*8.00 pesos + U*9.00 pesos ≥ 180 pesos.

And you also want to sell two of each, then:

C ≥ 2

U ≥2

So the system of inequalities is:

C*8.00 pesos + U*9.00 pesos ≥ 180 pesos.

C ≥ 2

U ≥2

If U is on the x-axis, and C is on the y-axis, then the graph is: (where the region at the right of the vertical line should be shaded)

6 0

3 years ago

Write the given differential equation in the form L(y) = g(x), where L is a linear differential operator with constant coefficie

melamori03 [73]

Answer:

The complete solution is

$\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43$

Step-by-step explanation:

Given differential equation is

3y"- 8y' - 3y =4

The trial solution is

$y = e^{mx}$

Differentiating with respect to x

$y'= me^{mx}$

Again differentiating with respect to x

$y''= m ^2 e^{mx}$

Putting the value of y, y' and y'' in left side of the differential equation

$3m^2e^{mx}-8m e^{mx}- 3e^{mx}=0$

$\Rightarrow 3m^2-8m-3=0$

The auxiliary equation is

$3m^2-8m-3=0$

$\Rightarrow 3m^2 -9m+m-3m=0$

$\Rightarrow 3m(m-3)+1(m-3)=0$

$\Rightarrow (3m+1)(m-3)=0$

$\Rightarrow m = 3, -\frac13$

The complementary function is

$y= Ae^{3x}+Be^{-\frac13 x}$

y''= D², y' = D

The given differential equation is

(3D²-8D-3D)y =4

⇒(3D+1)(D-3)y =4

Since the linear operation is

L(D) ≡ (3D+1)(D-3)

For particular integral

$y_p=\frac 1{(3D+1)(D-3)} .4$

$=4.\frac 1{(3D+1)(D-3)} .e^{0.x}$ [since $e^{0.x}=1$ ]

$=4\frac{1}{(3.0+1)(0-3)}$ [ replace D by 0 , since L(0)≠0]

$=-\frac43$

The complete solution is

y= C.F+P.I

$\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43$

4 0

3 years ago

Find the distance CD rounded to the nearest tenth<br> C=(10,-1) and D=(-6,3)

Fynjy0 [20]

Answer:

CD = 16.5

Step-by-step explanation:

To find the distance between two points, use this formula: $L = \sqrt{(x_{2} -x_{1})^{2}+(y_{2} -y_{1})^{2} }$

point C can be info set 1: (10, -1) x₁ = 10 y₁ = -1

point D can be info set 2: (-6, 3) x₂ = -6 y₂ = 3

Substitute the information into the formula

$L = \sqrt{(x_{2} -x_{1})^{2}+(y_{2} -y_{1})^{2} }$

$CD = \sqrt{(-6 -10)^{2}+(3 -(-1))^{2} }$ Simplify inside each bracket

$CD = \sqrt{(-16)^{2}+(4)^{2} }$ Square the numbers

$CD = \sqrt{256+16 }$ Add inside the root

$CD = \sqrt{272}$ Enter into calculator

$CD = 16.5$ Rounded to the nearest tenth, the first decimal

The distance CD is 16.5.

4 0

3 years ago

First twelve mulitples of 4

Pachacha [2.7K]

Answer:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48

Step-by-step explanation:

4*1 = 4

4*2 = 8

4*3 = 12

and so on...

5 0

3 years ago

Read 2 more answers

Paul is taking inventory of unsold ladies’ dresses from last month. The following matrix shows how many of each dress were left

Allisa [31]

Answer:

A

Step-by-step explanation:

Just add both matrices

5 0

3 years ago

Read 2 more answers