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Tresset [83]
3 years ago
11

Given that x overbarequals3.6667​, s Subscript xequals2.0656​, y overbarequals4.2167​, s Subscript yequals1.5613​, and requalsne

gative 0.9344​, determine the​ least-squares regression line.
Mathematics
1 answer:
Shtirlitz [24]3 years ago
6 0

Answer:

y = 0.7063x+2.7790

Step-by-step explanation:

Given that

x bar = 3.6667\\s_x= 2.0656\\y bar = 4.2167\\s_7 = 1.5613\\r = -0.9344

We have slope of linear regression line is

a=r*\frac{s_y}{s_x} =0.9344(\frac{1.5613}{2.0656} )\\=0.7063

So regression line would be of the form

y-4.2167 = 0.7063(x-2.0656) (since it passes through xbar, y bar)

y = 0.7063x+2.7790

is the equation of regression line.

You might be interested in
Find Horizontal and Vertical asymptotes for y=(x^2 -9)/(4x^2 +1)
Gnom [1K]

Answer: Horizontal asymptote is \dfrac{1}{4} and vertical asymptotes are \pm \dfrac{1}{2i}

Step-by-step explanation:

Since we have given that

y=\dfrac{x^2-9}{4x^2+1}

We need to find the horizontal and vertical asymptotes.

Since vertical asymptotes will occur where the denominator becomes zero.

So, here denominator is 4x^2+1

Now,

4x^2+1=0\\\\4x^2=-1\\\\x^2=\dfrac{-1}{4}\\\\x=\pm \dfrac{1}{2i}

And the horizontal asympototes will occur when the coefficient of higher degree of numerator is divided by coefficient of higher degree of denominator.

y=\dfrac{1}{4}

Hence, horizontal asymptote is \dfrac{1}{4} and vertical asymptotes are \pm \dfrac{1}{2i}

8 0
3 years ago
Solve y=x^2-5 for x​
Natasha_Volkova [10]

Answer:

x^2 - 5 = y

x^2= y + 5

x \:  =  \:  \sqrt{y + 5}

7 0
3 years ago
Hugo is mixing blue paint with red paint to create purple paint. The ratio of blue to red is 3 to 2. How many pints of blue pain
AysviL [449]
From my calculations I got :
- 24 pints of blue paint
- 16 pints of red paint
3 0
3 years ago
50 multiplied by 100
ra1l [238]
When multiplying by 100 just add 2 zero's behind your second number. ANSWER:5,000
3 0
3 years ago
Write the equation of the line that passes through (3, 4) and (2, −1) in slope-intercept form.
3241004551 [841]
(3,4)(2,-1)
slope(m) = (y2 - y1) / (x2 - x1)
slope(m) = (-1-4) / (2 - 3) = -5/-1 = 5

y = mx + b
slope(m) = 5
u can use either of ur points...(3,4)...x = 3 and y = 4
now we sub and find b, the y int
4 = 5(3) + b
4 = 15 + b
4 - 15 = b
- 11 = b

so ur equation is : y = 5x - 11 <===

3 0
3 years ago
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