Three students spent $12 on school lunch. At that rate, find the amount 10 students would spend on the same school lunch.
2 answers:
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Answer:
And the best option would be:
D. (0.191 to 0.249)
Step-by-step explanation:
For this case we know that the mean is:
And the standard error is given by:
We want to construct a 68% confidence interval so then the significance level would be :
and
. The confidence interval is given by:
Now we can find the critical value using the normal standard distribution and we got looking for a quantile who accumulate 0.16 of the area on each tail and we got:
And replacing we got:
And the best option would be:
D. (0.191 to 0.249)