Question

What is an equation in point-slope form for the line that contains the points (-1, 4) and (11, -6)?

Answer 1

Answer:

The equation in point-slope form is $y-4=-\frac{5}{6}(x+1)$

Step-by-step explanation:

Given points are;

(-1, 4) and (11, -6)

We will find the slope of the line through the given points.

Slope = m = $\frac{y_2-y_1}{x_2-x_1}$

m = $\frac{-6-4}{11-(-1)}$

m = $\frac{-10}{12}$

m = $\frac{-5}{6}$

Point slope form of a line is given by;

$y-y_1=m(x-x_1)$

Putting the point (-1,4) and slope in the equation

$y-4=-\frac{5}{6}(x-(-1))\\y-4 =-\frac{5}{6}(x+1)$

Hence,

The equation in point-slope form is $y-4=-\frac{5}{6}(x+1)$