Question

Passing through the point and perpendicular to the given line(-2,-2);y=-1/5x+9

Answer 1

Answer:

y = 5x + 8

Step-by-step explanation:

the equation of a line in slope-intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = - $\frac{1}{5}$ x + 9 is in this form

with slope m = - $\frac{1}{5}$

given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$, hence

$m_{perpendicular}$ = - 1 / - $\frac{1}{5}$ = 5

y = 5x + c ← is the partial equation

to find c substitute (- 2, - 2) into the partial equation

- 2 = - 10 + c ⇒ c = - 2 + 10 = 8

y = 5x + 8 ← equation of perpendicular line