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3 years ago

PLEASE ASSIST ME WITH THIS

Mathematics

2 answers:

kobusy [5.1K]3 years ago

7 0

The electric car is not moving at 0 seconds and 12 seconds

GuDViN [60]3 years ago

3 0

The electric car is not moving at 0 seconds and 12 seconds. Since y represents the speed in mph, if the car is moving at 0 mph, then it is not moving at all. 0 and 12 seconds show the car is moving at 0 mph.

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Suppose I ask you to pick any four cards at random from a deck of 52, without replacement, and bet you one dollar that at least

Tatiana [17]

Answer:

a) No, because you have only 33.8% of chances of winning the bet.

b) No, because you have only 44.7% of chances of winning the bet.

Step-by-step explanation:

a) Of the total amount of cards (n=52 cards) there are 12 face cards (3 face cards: Jack, Queen, or King for everyone of the 4 suits: clubs, diamonds, hearts and spades).

The probabiility of losing this bet is the sum of:

- The probability of having a face card in the first turn

- The probability of having a face card in the second turn, having a non-face card in the first turn.

- The probability of having a face card in the third turn, having a non-face card in the previous turns.

- The probability of having a face card in the fourth turn, having a non-face card in the previous turns.

1) The probability of having a face card in the first turn

In this case, the chances are 12 in 52:

$P_1=P(face\, card)=12/52=0.231$

2) The probability of having a face card in the second turn, having a non-face card in the first turn.

In this case, first we have to get a non-face card (there are 40 in the dech of 52), and then, with the rest of the cards (there are 51 left now), getting a face card:

$P_2=P(non\,face\,card)*P(face\,card)=(40/52)*(12/51)=0.769*0.235=0.181$

3) The probability of having a face card in the third turn, having a non-face card in the first and second turn.

In this case, first we have to get two consecutive non-face card, and then, with the rest of the cards, getting a face card:

$P_3=(40/52)*(39/51)*(12/50)\\\\P_3=0.769*0.765*0.240=0.141$

4) The probability of having a face card in the fourth turn, having a non-face card in the previous turns.

In this case, first we have to get three consecutive non-face card, and then, with the rest of the cards, getting a face card:

$P_4=(40/52)*(39/51)*(38/50)*(12/49)\\\\P_4=0.769*0.765*0.76*0.245=0.109$

With these four probabilities we can calculate the probability of losing this bet:

$P=P_1+P_2+P_3+P_4=0.231+0.181+0.141+0.109=0.662$

The probability of losing is 66.2%, which is the same as saying you have (1-0.662)=0.338 or 33.8% of winning chances. Losing is more probable than winning, so you should not take the bet.

b) If the bet involves 3 cards, the only difference with a) is that there is no probability of getting the face card in the fourth turn.

We can calculate the probability of losing as the sum of the first probabilities already calculated:

$P=P_1+P_2+P_3=0.231+0.181+0.141=0.553$

There is 55.3% of losing (or 44.7% of winning), so it is still not convenient to bet.

5 0

4 years ago

In his first year, a math teacher earned $32,000. Each successive year, he

Ivan

Answer:

Step-by-step explanation:

Each successive year, he

earned a 5% raise. It means that the salary is increasing in geometric progression. The formula for determining the nth term of a geometric progression is expressed as

Tn = ar^(n - 1)

Where

a represents the first term of the sequence(amount earned in the first year).

r represents the common ratio.

n represents the number of terms(years).

From the information given,

a = $32,000

r = 1 + 5/100 = 1.05

n = 20 years

The amount earned in his 20th year, T20 is

T20 = 32000 × 1.05^(20 - 1)

T20 = 32000 × 1.05^(19)

T20 = $80862.4

To determine the his total

earnings over the 20-year period, we would apply the formula for determining the sum of n terms, Sn of a geometric sequence which is expressed as

Sn = (ar^n - 1)/(r - 1)

Therefore, the sum of the first 20 terms, S20 is

S20 = (32000 × 1.05^(20) - 1)/1.05 - 1

S20 = (32000 × 1.653)/0.05

S20 = $1057920

3 0

3 years ago

Help me I am stuck in math!!!!!!

Archy [21]

I’m bad at math too sorry i can’t helppp i just need to answer one to ask a question

4 0

3 years ago

Read 2 more answers

The statement "if x is divisible by 8, then it is divisible by 6" is false if x equals

kotegsom [21]

$Answer:(3)\ 32\\\\32\ is\ divisible\ by\ 8\to32:8=4\\\\but\ not\ divisible\ by\ 6\to32:6=5\frac{1}{3}$

6 0

3 years ago

Read 2 more answers

Help me on my review quiz. 10 point btw

arsen [322]

Answer:

96.8 percent

Step-by-step explanation:

You can cut off two zeros from both numbers to compare 1000 to 32.

The difference is 968, and the original is 1000.

So you divide 968 by 1000 to get 0.968 which is equal to 96.8 percent.

6 0

3 years ago