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Vlad1618 [11]
3 years ago
12

2a - 5d = 30 dove for d

Mathematics
2 answers:
Slav-nsk [51]3 years ago
6 0
I hope this helps you




2a-30= 5d


d=2a-30/5


d=2a/5-6
AfilCa [17]3 years ago
5 0

2a - 5d = 30 solve for d

subtract 2a to both sides

2a - 5d - 2a = 30 - 2a

simplify

-5d = 30 - 2a

divide both sides by -5

-5d/-5 = (30 - 2a) / -5

simplify

d = -6 +0.4a

d = 0.4a - 6

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Find S5 for a geometric series for which a1=81 and r=1/9.
Minchanka [31]

ANSWER

S_5=91\frac{10}{81}




EXPLANATION


The sum of the first n terms of a geometric sequence is given by;


S_n=\frac{a_1(1-r^n)}{1-r} ,-1


Where n, is the number of terms and a_1 is the first term.


When n=5, we have a_1=81, we get;


S_5=\frac{81(1-(\frac{1}{9})^5)}{1-\frac{1}{9}}


S_5=\frac{81(1-\frac{1}{59049})}{1-\frac{1}{9}}


S_5=\frac{81(\frac{59048}{59049})}{\frac{8}{9}}




S_5=\frac{7381}{81}


S_5=91\frac{10}{81}




6 0
3 years ago
A group of four boys (Alex, Bryan, Chris, and David) and five girls (Megan, Nancy, Olivia, Pauline, and Rebecc?
aliina [53]

Answer:

a) P = 362880 ways

b) P = 2880 ways

Step-by-step explanation:

a) We have four boys and five girls, they are going to sit together in a row of 9 theater seats, without restrictions

We have a permutation of 9 elements

P = 9!

P = 9*8*7*6*5*4*3*2*1

P = 362880 ways

b) Boys must seat together, we have two groups of people

4 boys  they can seat in 4! different ways

P₁ = 4!

P₁ = 4*3*2*1

P₁ = 24

And girls can seat in 5! dfferent ways

P₂ = 5!

P₂ = 5*4*3*2*1

P₂ = 120

To get total ways in the above mentioned condition, we have to multiply P₁*P₂

P = 24*120

P = 2880 ways

4 0
3 years ago
Evaluate Ic2 + b2l, given a = 5, b = -3, and c= -2.
LenKa [72]

Answer:

Ic² + b²l = 13 units.

Step-by-step explanation:

We have to evaluate the expression Ic² + b²l with unknowns b and c and having the values of b and c respectively - 3 and - 2.

Now, Ic² + b²l

= I(- 2)² + (- 3)²l {Putting the values of b and c}

= I4 + 9l  

= I13l

= 13 units.

Therefore, Ic² + b²l = 13 units. (Answer)

5 0
3 years ago
1 pt) If a parametric surface given by r1(u,v)=f(u,v)i+g(u,v)j+h(u,v)k and −4≤u≤4,−4≤v≤4, has surface area equal to 1, what is t
natta225 [31]

The area of the surface given by \vec r_1(u,v) is 1. In terms of a surface integral, we have

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By multiplying each component in \vec r_1 by 5, we have

\dfrac{\partial\vec r_2(u,v)}{\partial u}=5\dfrac{\partial\vec r_1(u,v)}{\partial u}

and the same goes for the derivative with respect to v. Then the area of the surface given by \vec r_2(u,v) is

\displaystyle\int_{-4}^4\int_{-4}^425\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv=\boxed{25}

8 0
3 years ago
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anygoal [31]

Answer:

C

X=-16

Step-by-step explanation:

5 0
3 years ago
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