The <em>correct answer</em> is:
C) The set of all points in a plane that are equidistant from two points.
Explanation:
The set of all points in a plane that are equidistant from a given point and a given line is a parabola.
The set of all points in a plane at a given distance from a given point is a circle.
The set of all points in a plane that are equidistant from two points is a line.
The set of all points in a plane that are equidistant from three points is a plane.
6/10, 9/15,12/20, 15/25,...30/50, 33/55...300/500...
SA of triangular prism :
2B + Ph
Answer:
r = c -km÷m
Step-by-step explanation:
C=( r+k) m (multiple the m with the letters in the brackets)
rm + km= c (cross the km over the equal sign and it will be a negative)
rm= c- km (then divide everything by my)
rm÷m = c - km÷ m
r = c- km÷ m
Excercise 1:
No, this is not simplified fully. The full answer would be <span>−7dk+14d−21k</span>−7, not <span>14d - 9 - 21k - 7dk + 2. So, it is not equivalent.
</span><span>
Excercise 4:
</span><span>7dk (2 - 3 - 1) - 7
</span>
Just multiply 7dk into (2) (-3) and (-1)
you'd get:
<span><span>−<span>14dk</span></span>+</span>−<span>7 after simplifying it fully.
</span>
p = parameter
w = width
w+2.75
p = 2w+2(w+2.75) = <span>4w</span>+<span>5.5 = 30
Answer to the last one:
w = 6.125</span>
