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2 years ago

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Question 1(Multiple Choice Worth 4 points) (04.07A) Two quantities are related, as shown in the table below: x y 2 2 4 5 6 8 8 1

1 Which equation best represents the relationship? y = 3 over 2x + 2 y = 3 over 2x y = 3 over 2x − 1 y = 3x + 2

1 answer:

Tasya [4]2 years ago

6 0

Answer:

id say C if not sorry

Step-by-step explanation:

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2,5, 25/2, ... <br> find the 10th term

notka56 [123]

Answer:

The $10^{th}$ term of the given sequence

$t_{10} = \frac{5^{9} }{2^{8} }$

Step-by-step explanation:

<u>Step(i):-</u>

Given sequence 2 , 5, $\frac{25}{2}$

First term a = 2

The difference of given geometric sequence

$d = \frac{r_{2} }{r_{1} } = \frac{5}{2}$

<u><em>Step(ii):-</em></u>

The $n^{th}$ term of the given sequence

$t_{n} = ar^{n-1}$

The $10^{th}$ term of the given sequence

$t_{10} = (2)(\frac{5}{2} )^{10-1}$

$t_{10} = (2)(\frac{5}{2} )^{9}= \frac{5^{9} }{2^{8} }$

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3 years ago

How do u solve 5x + 9 = x - 23 ? *EXTRA POINTS

iren [92.7K]

Answer:

5x+9=x-23

5x-x=-23-9

4x= -32

4x/4=-32/4

x=-8

7 0

2 years ago

Read 2 more answers

Find the measures of the angles of the triangle whose vertices are A = (-3,0) , B = (1,3) , and C = (1,-3).A.) The measure of ∠A

alekssr [168]

Answer:

$\theta_{CAB}=128.316$

$\theta_{ABC}=25.842$

$\theta_{BCA}=25.842$

Step-by-step explanation:

A = (-3,0) , B = (1,3) , and C = (1,-3)

We're going to use the distance formula to find the length of the sides:

$r= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}$

$AB= \sqrt{(-3-1)^2+(0-3)^2}=5$

$BC= \sqrt{(1-1)^2+(3-(-3))^2}=9$

$CA= \sqrt{(1-(-3))^2+(-3-0)^2}=5$

we can use the cosine law to find the angle:

it is to be noted that:

the angle CAB is opposite to the BC.

the angle ABC is opposite to the AC.

the angle BCA is opposite to the AB.

to find the CAB, we'll use:

$BC^2 = AB^2+CA^2-(AB)(CA)\cos{\theta_{CAB}}$

$\dfrac{BC^2-(AB^2+CA^2)}{-2(AB)(CA)} =\cos{\theta_{CAB}}$

$\cos{\theta_{CAB}}=\dfrac{9^2-(5^2+5^2)}{-2(5)(5)}$

$\theta_{CAB}=\arccos{-\dfrac{0.62}}$

$\theta_{CAB}=128.316$

Although we can use the same cosine law to find the other angles. but we can use sine law now too since we have one angle!

To find the angle ABC

$\dfrac{\sin{\theta_{ABC}}}{AC}=\dfrac{\sin{CAB}}{BC}$

$\sin{\theta_{ABC}}=AC\left(\dfrac{\sin{CAB}}{BC}\right)$

$\sin{\theta_{ABC}}=5\left(\dfrac{\sin{128.316}}{9}\right)$

$\theta_{ABC}=\arcsin{0.4359}\right)$

$\theta_{ABC}=25.842$

finally, we've seen that the triangle has two equal sides, AB = CA, this is an isosceles triangle. hence the angles ABC and BCA would also be the same.

$\theta_{BCA}=25.842$

this can also be checked using the fact the sum of all angles inside a triangle is 180

$\theta_{ABC}+\theta_{BCA}+\theta_{CAB}=180$

$25.842+128.316+25.842$

$180$

6 0

3 years ago

Read 2 more answers

Write the explicit formula which can be used to represent the sequence 5,9,13,17

Oliga [24]

Answer:

4n+1

Step-by-step explanation:

Term 1: 4(1)+1 = 5

Term 2: 4(2)+1 = 9

Term 3: 4(3)+1 = 13

Term 4: 4(4)+1 = 17

4 0

3 years ago

Twice a certain number is 58. 4 times that number will be <br> a) 4x58 b) 58 + 4 c) 58x2 d)8x58

irga5000 [103]

Answer:

c) 58x2

Step-by-step explanation:

Twice the number 29 is 58

So, 29 is related to 58

Therefore 29*4 = 58*2

4 0

2 years ago