Answer:
128 ft / second.
Step-by-step explanation:
It's acceleration is due to gravity and is 32 ft s^-2.
To find the velocity when it hits the ground we use the equation of motion
v^2 = u^2 + 2gs where u = initial velocity, g = acceleration , s = distance.
v^2 = 0^2 + 2 * 32 * 256
v^2 = 16384
v = 128 ft s^-1.
g(x) = f(x) + 3
Since you know f(x) = 3x - 2, you can plug in (3x - 2) for "f(x)" in the equation:
g(x) = f(x) + 3
g(x) = (3x - 2) + 3
g(x) = 3x - 2 + 3
g(x) = 3x + 1
Answer:
A=0
Step-by-step explanation:
i think this is right if not im so sorry
Answer:
E(X) = 1.5
Var(X) = 2.325
Step-by-step explanation:
X - the number of pairs of cats (out of the 5 cats) to choose the same type of treat, can take values of:
X = (0, 1, 2, 3, 4, 5)
Also probability of choosing a treat, since they are all equally likely is: f(x) = 1/10
E(X) - expectation of x, is given by:
E(X) = Summation [X*f(x)]
E(X) = 0x(1/10) + 1x(1/10) + 2x(1/10) + 3x(1/10) + 4x(1/10) + 5x(1/10)
= (1/10) x (1+2+3+4+5)
E(X) = 3/2 = 1.5
Also, variance is:
Var(X) = Summation f(x)*[X - E(X)]^2
= (1/10)x(0-1.5)^2 + (1/10)x(1-1.5)^2 +(1/10)x(2-1.5)^2 +(1/10)x(3-1.5)^2 +(1/10)x(4-1.5)^2 +(1/10)x(5-1.5)^2
= (1/10)x[2.25 + 0.25 + 2.25 + 6.25 + 12.25]
Var(X) = 2.325
Answer:
57.6 km per hr
Step-by-step explanation:
Let us assume the horizontal distance between the ship is constant = x
= 70 Km
The ship A sails south at 40km/h is denoted as 40t
The Ship B sails north at 20 km/h is denoted as 20t
Now the vertical distance separating the two ships is
= 20t + 40t
= 60t
And, the Distance between the ship is changing
As x is constant
Now differentiating
The distance between two ships is at 4
So,
vertical distance is
= 240
And, the horizontal distance is 70
So, the distance between the ships is 57.6 km per hr