Speed and velocity is the answer
Answer:
SO you want me to figure out from year 2 or year4?
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
when you substitute 4 in x and 3 in y, your result are 11 no 10
a^2 - b^2 = (a + b)(a - b)
In this case
49x^4y^2 - 4z^2
= (7x^2y)^2 - (2z)^2
= (7x^2y + 2z)(7x^2y - 2z)
Factors are (7x^2y + 2z) and (7x^2y - 2z)
Answer:
D) 7x^2y + 2z
<h3>Answer: y = (3/2)x + 0</h3>
This is the same as y = (3/2)x
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Work Shown:
Find the slope of the line through (x1,y1) = (-2,-3) and (x2,y2) = (2,3)
m = (y2 - y1)/(x2 - x1)
m = (3 - (-3))/(2 - (-2))
m = (3 + 3)/(2 + 2)
m = 6/4
m = 3/2
The slope is the fraction 3/2. This is going to be in front of the x, or to the left of the x.
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Plug m = 3/2 and (x1,y1) = (-2,-3) into the point slope formula. Solve for y.
y - y1 = m(x - x1)
y - (-3) = (3/2)(x - (-2))
y + 3 = (3/2)(x + 2)
y + 3 = (3/2)x + (3/2)(2)
y + 3 = (3/2)*x + 3
y + 3 - 3 = (3/2)*x + 3 - 3
y = (3/2)x + 0
The y intercept is zero. This matches up with the fact the graph crosses the y axis at y = 0.
