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3 years ago

Please help me :((( thank you ! :(

Mathematics

2 answers:

ohaa [14]3 years ago

6 0

If you look at all of the problems, look at the signs first.
The symbol > means that the number to the left of it is larger than the number on the right. When this symbol has a line under it, then it is greater than or equal to the number on the right.
The symbol < means that the number to the left is less than the number on the right. When this symbol has a line under it, then it is less than or equal to the number on the right.
To satisfy each of the inequalities, you need to substitute the numbers for x.
For example, look at the first problem.
2(1) = 2
2(3) = 6
2(4) = 8
2(6) = 12
So, 2x is greater than or equal to 8 will be true if x = 8 or 12.

maxonik [38]3 years ago

4 0

1. 4
2. 12
3. 6
4. 18
5. 2
6. 4
7. 7
8. 15
9. 9

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Step-by-step explanation:

Standard form is written in the order of the exponent on a variable from highest to lowest.

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3 years ago

A basket contains 12 apples and some other fruit. Write an equation that could be used to find the total number of fruits in the

o-na [289]

A basket contains 12 apples and some other fruit
40% of the total fruit are apples...so 40% of the total fruit is 12..

0.40x = 12....with x being the total fruit in the basket <== ur equation
x = 12 / 0.40
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7 0

3 years ago

Zigmanuir [339]

Answer:

Ai. Arithmetic sequence

Aii. Tn = 5 + 7n

Bi. Geometric

Bii. Tn = 8 × 2ⁿ¯¹

Step-by-step explanation:

To successfully answer the questions given above, note the following:

1. If the sequence is Arithmetic, then:

2nd – 1st = 3rd – 2nd = common difference (d)

2. If the sequence is geometric, then,

2nd / 1st = 3rd / 2nd = common ratio (r)

3. A sequence can not be arithmetic geometric at the same time.

4. The nth term of arithmetic sequence is:

Tn = a + (n – 1)d

5. The nth term of geometric sequence is:

Tn = arⁿ¯¹

A. Sequence => 12, 19, 26

i. Determination of the type of sequence.

We'll begin by calculating the common difference

1st term = 12

2nd term = 19

3rd term = 26

Common difference (d) = 2nd – 1st

d = 19 – 12 = 7

d = 3rd – 2nd

d = 26 – 19 = 7

Since a common difference exist in the sequence, the sequence is arithmetic sequence.

ii. Determination of the nth term.

Common difference (d) = 7

1st term (a) = 12

nth term (Tn) =?

Tn = a + (n – 1)d

Tn = 12 + (n – 1)7

Tn = 12 + 7n – 7

Tn = 5 + 7n

B. Sequence => 8, 16, 32

Bi. Determination of the type of sequence.

Let us begin by calculating the common ratio.

1st term = 8

2nd term = 16

3rd term = 32

Common ratio (r) = 2nd / 1st

r = 16 / 8

r = 2

r = 3rd / 2nd

r = 32 / 16

r = 2

Since a common ratio exist in the sequence, the sequence is geometric.

Bii. Determination of the nth term.

Common ratio(r) = 2

1st term (a) = 8

nth term =?

Tn = arⁿ¯¹

Tn = 8 × 2ⁿ¯¹

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