Answer:
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- <u><em>Yes, it is reasonable to expect that more than one subject will experience headaches</em></u>
Explanation:
Notice that where it says "assume that 55 subjects are randomly selected ..." there is a typo. The correct statement is "assume that 5 subjects are randomly selected ..."
You are given the table with the probability distribution, assuming, correctly, the binomial distribution with n = 5 and p = 0.732.
- p = 0.732 is the probability of success (an individual experiences headaches).
- n = 5 is the number of trials (number of subjects in the sample).
The meaning of the table of the distribution probability is:
The probability that 0 subjects experience headaches is 0.0014; the probability that 1 subject experience headaches is 0.0189, and so on.
To answer whether it <em>is reasonable to expect that more than one subject will experience headaches</em>, you must find the probability that:
- X = 2 or X = 3 or X = 4 or X = 5
That is:
- P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5).
That is also the complement of P(X = 0) or P(X = 1)
From the table:
- P(X = 0) = 0.0014
- P(X = 1) = 0.0189
Hence:
- 1 - P(X = 0) - P(X = 1) = 1 - 0.0014 - 0.0189 = 0.9797
That is very close to 1; thus, it is highly likely that more than 1 subject will experience headaches.
In conclusion, <em>yes, it is reasonable to expect that more than one subject will experience headaches</em>
2(6a - 5) + 2(a + 1) =
= 12a - 10 + 2a + 2 =
= 12a + 2a - 10 + 2 = <u>1</u><u>4</u><u>a</u><u> </u><u>-</u><u> </u><u>8</u>
Answer:
Negative infinity, positive infinity
Step-by-step explanation:
The x values go forever in both ways
Answer: B. Graph of 2 lines that intersect at one point. Both lines are solid. One line passes through (-2,2) and (0,3) and is shaded below the line.
y < = 1/2x + 3...(-2,2) y < = 1/2x + 3....(0,3)
2 < = 1/2(-2) + 3 3 < = 1/2(0) + 3
2 < = -1 + 3 3 < = 0 + 3
2 < = 2 (correct) 3 < = 3 (correct)
The other line passes through points (0,1) and (1,-2) and is shaded above the line.
y > = -3x + 1...(0,1) y > = -3x + 1...(1,-2)
1 > = -3(0) + 1 -2 > = -3(1) + 1
1 > = 0 + 1 -2 > = -3 + 1
1 > = 1 (correct) -2 > = -2 (correct)
