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2 years ago

28 in 21 in., 20 in. Is this a right triangle?

Mathematics

1 answer:

ankoles [38]2 years ago

7 0

Answer:

No, it is not a right triangle.

Step-by-step explanation:

The simplest way to determine is testing out the numbers with Pythagorian theorem.

If it complies with the theorem, it is a right triangle.

let's assume c = 28, b = 21, and a = 20

the longest side is the hypotenuse so side c (28 in) will be the hypotenuse.

According to the Pythagorian theorem, the square of the length of hypotenuse must equal to the sum of squares of other two sides.

check:

c^2 = 28^2 = 784

a^2 + b^2 = 21^2 + 20^2 = 841

because c^2 is not equal to a^2 + b^2, the triangle is not a right triangle.

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Explanation:

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<h2>The area of the framed photograph = 1156 $inch^{2}$ </h2>

Step-by-step explanation:

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We know that,

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