All categories

3 years ago

The paragraph below comes from the rental agreement Susan signed when she opened her account at Super Video.

Mathematics

1 answer:

BARSIC [14]3 years ago

3 0

Answer:

option B

Step-by-step explanation:

Given:

per day late costs= 1.50

Purchase price= 9.99

A round trip cab ride to the video store will cost = 10

5 day late cost= 5(1.50)

= 7.50

Payment after 5 day late= 5 day late cost + Purchase price

= 7.50 + 9.99

= 17.49

If she gets a cab, then total payment= 10 + 7.50

= 17.50

Hence both costs almost the same, option B is true

It would cost about the same to keep or return the movie. Susan should keep it!

You might be interested in

Zoom in if beaded and pls help pronto

Bad White [126]

Answer is G. It won’t let me post answer unless it has 20 characters lol

8 0

2 years ago

Read 2 more answers

Find an equation of variation in which y varies directly as x and y=420 when x= 100. Then find the value of y when x=11.

sweet [91]

Let's Simplify X to equal 1 by dividing by 100. then we divide 420 by 100 to get 4.2, so y=4.2 when x=1, we then multiply by each by 11.

y = 46.2
x = 11

4 0

3 years ago

One positive number is 14 less than another positive number. If the reciprocal of the smaller number is added to five times the

Kipish [7]

Let's call the two numbers $s$ and $l$ .

Given these variables, we can say: $s = l - 14$ , based on the first sentence in the problem.

Also, remember that the reciprocal of a number is simply 1 divided by the number. Thus, we can say that:

$\dfrac{1}{s} + 5\Big( \dfrac{1}{l} \Big) = \dfrac{1}{4}$

To solve, we can simply substitute $l -14$ in for $s$ in the second equation and solve.

$\dfrac{1}{l - 14} + \dfrac{5}{l} = \dfrac{1}{4}$

Set up

$\dfrac{l}{l(l - 14)} + \dfrac{5(l - 14)}{l(l - 14)} = \dfrac{1}{4}$

Get terms on the left side to a common denominator for easier addition

$\dfrac{l + 5l - 70}{l(l - 14)} = \dfrac{1}{4}$

Simplify

$4(6l - 70) = l(l - 14)$

Cross multiplication ( $\frac{a}{b} = \frac{c}{d} \Rightarrow ad = bc$ )

$24l - 280 = l^2 - 14l$

Simplify

$l^2 - 38l + 280 = 0$

Subtract $24l - 280$ from both sides of the equation

$(l - 10)(l - 28) = 0$

Factor left side of the equation

$l = 10, 28$

Zero Product Property

Now, notice that we have found two solutions, but the problem is only asking for one. This <em>likely </em>means that one of our solutions is extraneous. Let's take a look. Remember that the smaller positive number is equal to 14 less than the larger number. However,

$s = 10 - 14 = -4$ ,