L=6+W
A=LW
sub 6+W for L
A=(6+W)(W)
expand
oh, A=50
50=W²+6W
minus 50 both sides
0=W²+6W-50
we gots to use quadratic formula
for
aW²+bW+c=0
W=
we got
a=1
b=6
c=-50
W=
W=
W=
W=
W=
W=
or W=
aprox
W=-10.6811 or W=4.68115
can't be negative width
width=4.68115 or -3√59
75% × x = 56 or, 75/100 × x = 56
Multiplying both sides by 100 and dividing both sides by 75,
we have x = 56 × 75/100
x = 74.667
6+0=6
When you add any number to 0, that number stays the same since you aren’t adding anything to it. So the answer is 6.
Answer:
The temperature outside is 75.6°F
Step-by-step explanation:
We are given the following in the question:
The temperature of dry ice = - 109.3°F
Let x be the temperature outside in Fahrenheit.
It is given that the temperature of dry ice is 184.9°F less than the outside temperature.
Thus, we can write the equation:
Solving, the above equation, we get:
Thus, the temperature outside is 75.6°F