Answer:
98
Step-by-step explanation:
96000000 times bigger. in scientific notation 9.6×10 to the 7th power
Answer: Choice B. sqrt(2)
Draw out a right triangle in quadrant IV as you see in the attached image below. The horizontal and vertical legs are both 1 unit long. To ensure that the signs are properly set up, I am making the vertical leg BC have a label "-1" to mean this is below the x axis. Note how
tan(theta) = opposite/adjacent = BC/AB = -1/1 = -1
Use the pythagorean theorem to find that the hypotenuse AC is sqrt(2) units long
a^2 + b^2 = c^2
(1)^2 + (1)^2 = c^2
2 = c^2
c^2 = 2
c = sqrt(2)
The secant of theta is the ratio of the hypotenuse over the adjacent side, so we end up with
sec(theta) = hypotenuse/adjacent
sec(theta) = AC/AB
sec(theta) = sqrt(2)/1
sec(theta) = sqrt(2) which is why choice B is the answer
ANSWER:
As we know, diagonals of parallelogram (||gm) bisect each other.
So, AE = EC
2x - 10 = 8x - 70
2x - 8x = - 70 + 10
- 6x = - 60
x = 10
Answer:
49π
Step-by-step explanation:
Circle area: πr^2
Since A to C is 14, and they're both in the center, A to B and B to C will both be 7 as a radius.
Since we know the radius, we can put it in the formula, πr^2.
We only need to solve for one circle, since both circles are the same. By solving the circle, we will put in 7 for the radius, giving us π7^2, which is 49π.