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muminat
3 years ago
15

If a pair of dice are rolled, what is the probability that at least one die shows a 5?

Mathematics
1 answer:
solmaris [256]3 years ago
6 0

Answer:

11/36

Step-by-step explanation:

Find the probability that neither dice shows a 5 (also means the dice can show any number except 5- where there are 5 possible choices out of 6):

= 5/6 x 5/6

=25/36

If we subtract the probability that neither dice shows a 5, we can obtain the probability that at least 1 dice shows a 5- (either one of them is 5, or both of them is 5)

1- 25/36

=11/36

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The first six composite numbers are 4, 6, 8, 9, 10, 12. Their average is their total divided by their number.

... 49/6 = 8 1/6

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What is the value of x in the equation 8 + x = 3?<br><br> A. −5<br> B. 5<br> C. 11<br> D. 24
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Answer:

I think it's A

I hope this helps

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3 years ago
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You cut a large chocolate cake into 8 equal pieces.  You sell 6 pieces of the cake. What fraction of the cake is left?
Luda [366]

8 - 6 = 2

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3 years ago
If six angles of a heptagon have measures of 122, 153, 168, 105, 162, and 87, what is the measure of the seventh angle?
xxTIMURxx [149]

Answer:

he seventh angles measure is 103

Step-by-step explanation:

Interior angles = (number of side in the polygon - 2) times 180.

So Heptagon interior angles = (7-2)(180) = 900

To find the missing angles add all the given angles together (122, 153, 168, 105, 162, and 87) = 797.

Now   The measure of the seventh angles = total angles measure - the six given angles,

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7 0
3 years ago
Hey guys how do you simplify this fully?​
Masja [62]

Answer:

32

Step-by-step explanation:

In 100^1000,

100 can be written as,

100 = 10 x 10 = 10^2

100^1000

= 10^( 2 * 1000 )

= 10^2000

10 can be written as,

10 = 2 x 5

10^2000

= ( 2 x 5 )^2000

Formula : -

( a x b )^n = a^n x b^n

Here,

a = 2

b = 5

n = 2000

( 2 x 5 )^2000 = 2^2000 x 5^2000

[ 2^2005 x 5^2000 ] / 100^1000

= [ 2^2005 x 5^2000 ] / [ 2^2000 x 5^2000 ]

Formula : -

a^m x b^n / a^c x b^d

= a^( m - c ) x b^( n - d )

Here,

a = 2

m = 2005

c = 2000

b = 5

n = d = 2000

[ 2^2005 x 5^2000 ] / [ 2^2000 x 5^2000 ]

= 2^( 2005 - 2000 ) x 5^( 2000 - 2000 )

= 2^5 x 5^0

{ Note : Any number power 0 ( except 0 ) is 1.

That is 0^0 ≠ 1, but 5^0 = 1. }

= 2^5 x 1

= 2^5

= 2 x 2 x 2 x 2 x 2

= 32

5 0
3 years ago
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