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Trava [24]
3 years ago
6

A pear costs x cents. An orange costs y cents less

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
8 0

Step-by-step explanation:

Pear cost=x

Orange cost=x-y

4 pears= 4x

6 oranges=6x-6y or x-y x6

Use ratio.

Pears: x cents

4 Pears: 6x cents

You x4 on each side. Same with oranges.

Orange: x-y

6 oranges: x-y x6

You x6 on each side.

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Use the grouping method to factor the polynomial below x^3 -4x^2+3x-12
olasank [31]

Answer:

x^2(x-4) + 3(x-4)

(x^2 + 3)(x-4)

Step-by-step explanation:

8 0
3 years ago
You have been assigned to determine whether more people prefer Coke or Pepsi. Assume that roughly half the population prefers Co
Alex Ar [27]

Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11  

And rounded up we have that n=1068

Step-by-step explanation:

For this case we have the following info given:

ME=0.03 the margin of error desired

Conf= 0.95 the level of confidence given

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

the critical value for 95% of confidence is z=1.96

We can use as estimator for the population of interest \hat p=0.5. And on this case we have that ME =\pm 0.03 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11  

And rounded up we have that n=1068

3 0
3 years ago
Which value goes in the empty cell?
Andrews [41]

Answer:

[See Below]

Step-by-step explanation:

If you replace the x with -1 and evaluate the function you get -5.

7 0
3 years ago
Read 2 more answers
Write
IRISSAK [1]

Answer:

y = 2 ( x − 1 ) ^ 2 + 2

Step-by-step explanation:

y = a ( x − h ) ^ 2 + k

where vertex is (h,k) = (1,2)

h=1, k=2

y = a ( x − 1 ) ^ 2 + 2

sub ( 3,10)

10 = a (3 - 1)^2 + 2

a=2

y = 2 ( x − 1 ) ^ 2 + 2

7 0
3 years ago
What is the difference of the polynomials?<br><br> (–2x3y2 + 4x2y3 – 3xy4) – (6x4y – 5x2y3 – y5)
ANEK [815]
For the answer to the question above, I'll provide my solutions to my answers for the problem below.

(–2x3y2 + 4x2y3 – 3xy4) – (6x4y – 5x2y3 – y5)

(−2x3)(y2)+4x2y3+−3xy4+−1(6x4y)+−1(−5x2y3)+−1(−y5)

(−2x3)(y2)+4x2y3+−3xy4+−6x4y+5x2y3+y5

−2x3y2+4x2y3+−3xy4+−6x4y+5x2y3+y5

−2x3y2+4x2y3+−3xy4+−6x4y+5x2y3+y5

(−6x4y)+(−2x3y2)+(4x2y3+5x2y3)+(−3xy4)+(y5)

−6x4y+−2x3y2+9x2y3+−3xy4+y5
So the answer is,
= <span><span><span><span><span>−<span><span>6x4</span>y</span></span>−<span><span>2x3</span>y2</span></span>+<span><span>9x2</span>y3</span></span>−<span>3xy4</span></span>+y5</span> 

I hope this helps
4 0
3 years ago
Read 2 more answers
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