Answer:
3.25=x
Step-by-step explanation:
start with -5=4x+8
subtract 8 from each side to get:
-13=4x
divide each side by 4 to get your answer:
-3.25=x-
Answer:
Here's what I get.
Step-by-step explanation:
9. (6, -8)
The reference angle θ is in the fourth quadrant.
∆AOB is a right triangle.
OB² = OA² + AB² = 6² + (-8)² = 36 + 64 = 100
OB = √100 = 10

10. cot θ = -(√3)/2
The reference angle θ is in the second quadrant.
∆AOB is a right triangle.
OB² = OA² + AB² = (-√3)² + (2)² = 3 + 4 = 7
OB = √7

Answer:
approximately 1,148,000
Step-by-step explanation:Round 2,803 to 2,800 and 406 to 410 then multiply 2,800 by 410
Answer:
-6x⁶ + 4x⁴ - 3x³ + 4x² + 12
Step-by-step explanation:
To write an equation in standard form, you want to arrange the terms from increasing to decreasing powers/exponents.
given: 4x² - 6x⁶ + 2x³ + 12 - 5x³+ 4x⁴
First, lets arrange like terms together. Put the terms with the same exponent together.
2x³ - 5x³ + 4x² - 6x⁶ + 12 + 4x⁴
Now combine the terms with the same exponent by subtracting 5x³ from 2x³.
-3x³ + 4x² - 6x⁶ + 12 + 4x⁴
Now let's arrange the terms from increasing to decreasing powers/exponents.
-6x⁶ + 4x⁴ - 3x³ + 4x² + 12
This is your equation in standard form.
Hope this helps!
Answer:
12 fiction books.
Step-by-step explanation:
Let b represent number of non-fiction books.
We have been given that in the library at Lenape elementary school, there are 3/8 as many fiction books as there are nonfiction books. So number of fiction books would be
.
We are also told that there are 44 books in school library. We can represent this information in an equation as:

Let us solve for x.






Therefore, there are 32 non fiction books in the library.
Number of fiction books would be 
Therefore, there are 12 fiction books in the library.