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Nonamiya [84]
3 years ago
6

What integer is equivalent to 25 3/2

Mathematics
2 answers:
antiseptic1488 [7]3 years ago
3 0
<span><span><u>Answer</u>
26 1/2 is not equivalent to and integer but it can be approximated to 27 which is an integer.

<u>Explanation</u>
An integer is a whole number. It is a number that is not a fraction.
253/2=25+3/2=25+1 1/2=26 1/2
</span><span>26 1/2 is not equivalent to and integer but it can be approximated to 27 which is an integer.
</span></span>
schepotkina [342]3 years ago
3 0

<u>Answer:</u> The integer equivalent to the given number is 27.

<u>Step-by-step explanation:</u>

To write the integer which is equivalent to the given number, we will first simplify the given number.

As, it is a mixed fraction, the simplification of this occurs:

a\frac{b}{c}=\frac{(a\times c)+b}{c}

So, simplifying the given mixed fraction, 25\frac{3}{2}, we get:

25\frac{3}{2}=\frac{(25\times 2)+3}{2}=\frac{53}{2}=26.5

Integer is defined as the number which is not expressed in a fraction or decimal number. If the number is in fraction or decimal, we simplify and round it off to the nearest whole number.

Rounding off rules:

If the decimal digit is less than 5, then it is rounded off to the lower whole number and if the decimal digit is equal or greater than 5, then it is rounded off to the upper whole number.

26.5\approx 27

Hence, the integer equivalent to the given number is 27.

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The volume of a cuboid is 2160cm3. The length is 12cm and the width is 150mm. Work out the height of the cuboid in cm.
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Answer:

12 cm

Step-by-step explanation:

12x15 (150)

2160/180

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8 0
2 years ago
Three times the sum of a number and 21 is at most -26
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It would be: 3(x + 21) ≤ -26
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3x ≤ -47
x < -47/3

In short, Your Answer would be -47/3 or 15.67

Hope this helps!

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3 years ago
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2 years ago
A 20.3 kg person climbs up a uniform ladder with negligible mass. The upper end of the ladder rests on a frictionless wall. The
VMariaS [17]

Answer:

Q = arctan(7.1739) = 82.06

Step-by-step explanation:

Given:

- The mass of the person m = 20.3 kg

- The distance traveled up the ladder s = 1.1 m

- The gravitational constant g = 9.8 m/s^2

- The coefficient of static friction u_s = 0.23

- Total length of the ladder

Find:

The minimum angle θ, that would allow the person to climb without ladder slipping

Solution:

- Taking moments about point of ladder and wall contact A to be zero:

                   -F_n,b*cos(Q)*4 - F_f*sin(Q)*4+ m*g*cos(Q)*2.6 = 0

- Taking Sum of vertical forces to be zero:

                    F_n,b - m*g = 0

                    F_n,b = m*g

- The frictional force F_f is given by:

                   F_f = u_s*F_n,b = u_s*m*g

- Plug the values back in:

                  - m*g*cos(Q)*4 + u_s*m*g*sin(Q)*4 - m*g*cos(Q)*2.6 = 0

Simplify:

                  4*cos(Q) + 2.6*cos(Q) = u_s*4*sin(Q)

                        6.6*cos(Q) = 4*u_s*sin(Q)

                               tan(Q) = 6.6 / 4*u_s

- Plug in the values:

                               tan(Q) = 6.6 / 4*0.23

                                    Q = arctan(7.1739) = 82.06

                   

                     

4 0
3 years ago
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