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3 years ago

What integer is equivalent to 25 3/2

2 answers:

3 0

Answer
26 1/2 is not equivalent to and integer but it can be approximated to 27 which is an integer.

Explanation
An integer is a whole number. It is a number that is not a fraction.
253/2=25+3/2=25+1 1/2=26 1/2
26 1/2 is not equivalent to and integer but it can be approximated to 27 which is an integer.

schepotkina [342]3 years ago

3 0

Answer: The integer equivalent to the given number is 27.

Step-by-step explanation:

To write the integer which is equivalent to the given number, we will first simplify the given number.

As, it is a mixed fraction, the simplification of this occurs:

$a\frac{b}{c}=\frac{(a\times c)+b}{c}$

So, simplifying the given mixed fraction, $25\frac{3}{2}$ , we get:

$25\frac{3}{2}=\frac{(25\times 2)+3}{2}=\frac{53}{2}=26.5$

Integer is defined as the number which is not expressed in a fraction or decimal number. If the number is in fraction or decimal, we simplify and round it off to the nearest whole number.

Rounding off rules:

If the decimal digit is less than 5, then it is rounded off to the lower whole number and if the decimal digit is equal or greater than 5, then it is rounded off to the upper whole number.

$26.5\approx 27$

Hence, the integer equivalent to the given number is 27.

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3 years ago

Find f. A) 7.4 B) 8.2 C) 10.5 D) 11.1

tatyana61 [14]

F=72

g=6

------------

$\cos { \left( F \right) } =\frac { { e }^{ 2 }+{ g }^{ 2 }-{ f }^{ 2 } }{ 2eg }$

Therefore:

$\cos { \left( 72 \right) } =\frac { { e }^{ 2 }+{ 6 }^{ 2 }-{ f }^{ 2 } }{ 2\cdot e\cdot 6 } \\ \\ \cos { \left( 72 \right) } =\frac { { e }^{ 2 }+36-{ f }^{ 2 } }{ 12e }$

$\\ \\ 12e\cdot \cos { \left( 72 \right) } ={ e }^{ 2 }+36-{ f }^{ 2 }\\ \\ \therefore \quad { f }^{ 2 }={ e }^{ 2 }-12e\cdot \cos { \left( 72 \right) } +36\\ \\ \therefore \quad f=\sqrt { { e }^{ 2 }-12e\cdot \cos { \left( 72 \right) +36 } } \\ \\ \therefore \quad f=\sqrt { e\left( e-12\cos { \left( 72 \right) } \right) +36 }$

But what is e?

E=76

G=32

g=6

And:

$\frac { e }{ \sin { \left( E \right) } } =\frac { g }{ \sin { \left( G \right) } }$

Which means that:

$\frac { e }{ \sin { \left( 76 \right) } } =\frac { 6 }{ \sin { \left( 32 \right) } } \\ \\ \therefore \quad e=\frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } }$

If you take this value into account, you will discover that f is...

$f=\sqrt { \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } \left( \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } -12\cos { \left( 72 \right) } \right) +36 } \\ \\ \therefore \quad f=10.8\quad \left( 1\quad d.p \right)$

So I would have to say that the answer is approximately (c).

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3 years ago