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3 years ago

15

David is building wooden picture frames. Each frame requires 3/4 feet of wood. If David started with 12 feet of wood and now has

6 feet of wood remaining, how many pictures frames has he built?

2 answers:

statuscvo [17]3 years ago

6 0

Answer:

0.75

Step-by-step explanation:

3241004551 [841]3 years ago

3 0

Answer:

8 picture frames would be built.

Step-by-step explanation:

David started with 12 feet's of wood

And has 6feets if wood remaining

Feets of wood used = 12 - 6 = 6feets

Each frame = 3/4 feets

1 picture frame = 3/4 feets

Number of pictures frames has he built =

X picture frame = 6 / (3/4)

X picture frames = 6 x 4/3

= 24/3 = 8

8 picture frames would be built.

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Natali5045456 [20]

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all you have to do is graph it as it is.

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3 years ago

Read 2 more answers

Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question. Listed below

mafiozo [28]

Answer:

a) $\bar X = 369.62$

b) $Median=175$

c) $Mode =450$

With a frequency of 4

d) $MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

<u>e)</u> $s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

Replacing we got:

$\bar X = 369.62$

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

$Median=175$

Part c

The mode is the most repeated value in the sample and for this case is:

$Mode =450$

With a frequency of 4

Part d

The midrange for this case is defined as:

$MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

Part e

For this case we can calculate the deviation given by:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

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3 years ago

In a diagram, X is the midpoint of Segment VZ. VW =5, and VY =20. Find the coordinates of W,X, and Y.

guapka [62]

solution:

$x(a_{x},b_{x})is midpoint of vz\\
a_{x}=\frac{a_{v}+a_{z}}{2}=\frac{-12+22}{2}=\frac{10}{2}=5\\
b_{x}=\frac{b_{v}+b_{z}}{2}=\frac{0+0}{2}=0\\
and,\\
x(5,0)\\
w(a_{w},b_{w}),v_{w} and w is on the right of v.\\
a_{w}-a_{v}=5\\
a_{w}-(-12)=5\\
a_{w}+12=5\\
a_{w}=5-12=-7\\
w(-7,0)\\
y(a_{y},b_{y})=20 and y is on the right of v.\\
a_{y}-a_{v}=20\\
a_{y}-(-12)=20\\
a_{y}+12=20\\
a_{y}=20-12=8\\
y=(8,0)$

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3 years ago

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Sloan [31]

Answer:

Sum of $\frac{7x}{x^2-4}$ and $\frac{2}{x+2}$ is $\mathbf{\frac{9x-4}{x^2-4}}$

Option B is correct answer.

Step-by-step explanation:

We need to find sum of $\frac{7x}{x^2-4}$ and $\frac{2}{x+2}$

Finding sum of $\frac{7}{x^2-4}$ and $\frac{2}{x+2}$ :

$\frac{7x}{x^2-4}+\frac{2}{x+2}$

We know that $x^2-4 =(x+2)(x-2)$

Replacing x^2-4

$\frac{7x}{(x+2)(x-2)}+\frac{2}{x+2}$

Now, taking LCM of (x+2)(x-2) and (x+2) we get (x+2)(x-2)

$=\frac{7x+2(x-2)}{(x+2)(x-2)}\\=\frac{7x+2x-4}{(x+2)(x-2)}\\=\frac{9x-4}{(x+2)(x-2)}\\=\frac{9x-4}{x^2-4}$

So, Sum of $\frac{7x}{x^2-4}$ and $\frac{2}{x+2}$ is $\mathbf{\frac{9x-4}{x^2-4}}$

Option B is correct answer.

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2 years ago

Mi is about to roll a six-sided number cube. What is the experimental probability that she will roll an even number based on her

Kryger [21]

Answer: The experimental probability that she will roll an even number= $\frac{1}{2}$

Step-by-step explanation:

We know that the probability for any event is given by6;-

$\text{Probability}=\frac{\text{Favorable outcomes}}{\text{Total outcomes}}$

In a dice, the total even numbers (2,4,6)= 3

Therefore, the probability that she will roll an even number will be given by:-

$\text{Probability}=\frac{\text{3}}{\text{6}}=\frac{1}{2}$

Hence, The experimental probability that she will roll an even number= $\frac{1}{2}$

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3 years ago