To find the 'maximum height' we will need to take the derivative of h(t) = –16t² + 32t + 6 then set it equal to zero, then solve for t. this t will be the time at which the ball reaches it's maximum height.
Answer:
C) 1
F) 29
Step-by-step explanation:
all numbers less than 30 are solutions
Answer:
Step-by-step explanation:
Δ = 
VΔ = 4 * 8 = 32
a = (- 4 ± 32) * 
a' = 7/2
a''= 9/2
C, i dont know dont use my answer unless you know
Answer:
$48 per unit
Step-by-step explanation:
Increasing the price by $5 reduces demand by 20 units, so the slope of the curve is -4 units per dollar. This lets us write a demand equation as ...
q = -4(p -50) +184
q = -4p + 384
q = 4(96 -p)
The revenue is the product of price and demand:
r = pq = 4p(96 -p)
This is the equation of a quadratic curve that opens downward and has zeros at p=0 and p=96. The vertex (maximum) will be halfway between the zeros, at ...
p = (0+96)/2 = 48
A price of $48 per unit will yield a maximum total revenue.
