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pychu [463]
3 years ago
14

Hello please help thanks

Mathematics
2 answers:
Sloan [31]3 years ago
7 0

Answer:

precipitation

Step-by-step explanation:

ira [324]3 years ago
5 0

Answer:

I would say Condensation

Step-by-step explanation:

Hope this helps you!

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The equation of this circle is (x + <br> )2 + (y + <br> )2 = <br> .
Alex787 [66]

Answer:

x2 + y2 = r2, and this is the equation of a circle of radius r whose center is the origin O(0, 0). The equation of a circle of radius r and center the origin is x2 + y2 = r2.

I think this is the answer.

7 0
2 years ago
Here is a sketch of y=x^2+bx+c The curve intersects
atroni [7]

Answer:

y = 18  and  x = -2

Step-by-step explanation:

y = x^2+bx+c   To find the turning point, or vertex, of this parabola, we need to work out the values of the coefficients b and c. We are given two different solutions of the equation. First, (2, 0).  Second, (0, -14). So we have a value (-14) for c. We can substitute that into our first equation to find b. We can now plug in our values for b and c into the equation to get its standard form. To find the vertex, we can convert this equation to vertex form by completing the square. Thus, the vertex is (4.5, –6.25). We can confirm the solution graphically     Plugging in  (2,0) :

y=x2+bx+c  

0=(2)^2+b(2)+c  

y=4+2b+c  

-2b=4+c  

b=-2+2c  

Plugging in  (0,−14) :

y=x2+bx+c  

−14=(0)2+b(0)+c  

−16=0+b+c  

b=16−c  

Now that we have two equations isolated for  b , we can simply use substitution and solve for  c .   y=x2+bx+c  16 + 2 = y   y = 18  and  x = -2

4 0
3 years ago
Which is the value of i^20+1?
Nonamiya [84]

Answer:

Step-by-step explanation:

i^{20}+1=i^{2*10}+1\\\\(i^{2})^{10}+1=(-1)^{10}+1\\\\=1+1=2

8 0
3 years ago
Solve for possible values of x. 3x^2 = 18x
uysha [10]

(0,0) and (6,0)

First we subtract 18x from both sides

3x²-18x=0

Factor out a 3x

3x(x-6)=0

This means that x is either 0 or 6

7 0
3 years ago
Read 2 more answers
Please help with this question.
andrew11 [14]

Answer:

p3+13=37

We move all terms to the left:

p3+13-(37)=0

We add all the numbers together, and all the variables

p^3-24=0

7 0
3 years ago
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