Answer:
3,090 diamonds
Step-by-step explanation:
To get 10 shards, you need to spend 30 diamonds.
First thing we need to find, how many rounds you need to play to get 1,024 shards if in each round you win 10 shards?
1,024/10 = 102,4
But you can not play 102.4 rounds, you only can play whole numbers, so we need to round it to the next whole number (not the previous one, because in that case, we would get less than 1,024 shards)
Then you need to play 103 rounds.
And each round costs 30 diamonds, then the total number of diamonds that you need is:
103*30 diamonds = 3,090 diamonds
Answer:
2.99 x 10⁸ meters per second
Step-by-step explanation:
Scientific notation (also called "Standard form") is written in the form of 
, where 
and 
is any positive or negative whole number.
To <u>convert</u> a number into <u>scientific notation</u>, move the decimal point to the left or right until there is <u>one digit before the decimal point.</u>
The number of times you have moved the decimal point is the power of 10 ().
If the decimal point has moved to the <u>left</u>, the power is <u>positive</u>.
If the decimal point has moved to the <u>right</u>, the power is <u>negative</u>.
<u>To convert the given number to scientific notation</u>
The decimal point for the given number 299000000 is after the last zero:
⇒ 299000000.
Move the decimal point 8 places to the left:
⇒ 2.99000000
Get rid of the redundant zeros:
⇒ 2.99
Multiply by 10 to the power of the number of decimal places moved:
⇒ 2.99 x 10⁸
Therefore, the speed of light using scientific notation is:
- 2.99 x 10⁸ meters per second
The answer would be D i believe
Answer:
Step-by-step explanation:
Given
P(1,-3); P'(-3,1)
Q(3,-2);Q'(-2,3)
R(3,-3);R'(-3,3)
S(2,-4);S'(-4,2)
By observing the relationship between P and P', Q and Q',.... we note that
(x,y)->(y,x) which corresponds to a single reflection about the line y=x.
Alternatively, the same result may be obtained by first reflecting about the x-axis, then a positive (clockwise) rotation of 90 degrees, as follows:
Sx(x,y)->(x,-y) [ reflection about x-axis ]
R90(x,y)->(-y,x) [ positive rotation of 90 degrees ]
combined or composite transformation
R90. Sx (x,y)-> R90(x,-y) -> (y,x)
Similarly similar composite transformation may be obtained by a reflection about the y-axis, followed by a rotation of -90 (or 270) degrees, as follows:
Sy(x,y)->(-x,y)
R270(x,y)->(y,-x)
=>
R270.Sy(x,y)->R270(-x,y)->(y,x)
So in summary, three ways have been presented to make the required transformation, two of which are composite transformations (sequence).
