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3 years ago

7

PLEASE HELP ME

1 answer:

e-lub [12.9K]3 years ago

8 0

Answer:

C

Step-by-step explanation:

y < 5 and y < 2 over lap at y < 2

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550 tickets were sold for a game for a total of $712.50. If adult tickets sold for $1.50 and children's tickets sold for $1.00,

EastWind [94]

9514 1404 393

Answer:

adult: 325
children's: 225

Step-by-step explanation:

It usually works well to let a variable represent the higher-value item in the mix. Here, we can let 'a' represent the number of adult tickets sold. Then the total revenue is ...

1.50a +1.00(550 -a) = 712.50

0.50a = 162.50 . . . . . . . . . . . . . subtract 550 and collect terms

a = 325

c = 550 -325 = 225

325 adult and 225 children's tickets were sold.

4 0

3 years ago

Write 5/6 in the lowest terms

Vanyuwa [196]

5 don't have lowest term only the 6 and it's 2 but if a number like 5 doesn't change so 6 doesn't change if not then divide 5 to 6.

6 0

3 years ago

Read 2 more answers

From the moment the first car started how many hours will it take the second car to catch up to the first

Rina8888 [55]

Answer:

HELP

Step-by-step explanation:

3 0

3 years ago

Which expression represents the number 2i4−5i3+3i2+−81‾‾‾‾√ rewritten in a+bi form?

vichka [17]

Answer:

The expression $-1+14i$ represents the number $2i^4-5i^3+3i^2+\sqrt{-81}$ rewritten in a+bi form.

Step-by-step explanation:

The value of $i$ is $i=\sqrt{-1}[tex] or [tex]i^{2}=-1[\tex].Now [tex]i^{4}$ in term of $i^{2}[\tex] can be written as, [tex]i^{4}=i^{2}\times i^{2}$

Substituting the value,

$i^{4}=\left(-1\right)\times \left(-1\right)$

Product of two negative numbers is always positive.

$\therefore i^{4}=1$

Now $i^{3}$ in term of $i^{2}[\tex] can be written as, [tex]i^{3}=i^{2}\times i$

Substituting the value,

$i^{3}=\left(-1\right)\times i$

Product of one negative and one positive numbers is always negative.

$\therefore i^{3}=-i$

Now $\sqrt{-81}$ can be written as follows,

$\sqrt{-81}=\sqrt{\left(81\right)\times\left(-1\right)}$

Applying radical multiplication rule,

$\sqrt{ab}={\sqrt{a}}\sqrt{b}$

$\sqrt{\left(81\right)\times\left(-1\right)}={\sqrt{81}}\sqrt{-1}$

Now, $\sqrt{\left(81\right)=9$ and $\sqrt{-1}}=i$

$\therefore \sqrt{\left(81\right)\times\left(-1\right)}=9i$

Now substituting the above values in given expression,

$2i^4-5i^3+3i^2+\sqrt{-81}=2\left(1\right)-5\left(-i\right)+3\left(-1\right)+9i$

Simplifying,

$2+5i-3+9i$

Collecting similar terms,

$2-3+5i+9i$

Combining similar terms,

$-1+14i$

The above expression is in the form of a+bi which is the required expression.

Hence, option number 4 is correct.

5 0

3 years ago

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melisa1 [442]

Hope it helps!! Happy holidays!!

6 0

3 years ago