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soldi70 [24.7K]
3 years ago
8

*20* points* any help would be appreciated

Mathematics
1 answer:
drek231 [11]3 years ago
4 0

Answer:

well I need a sec to remember what that is but be right back

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The rectangle below has an area of 8x^5+12x^3+20x^28x 5 +12x 3 +20x 2 8, x, start superscript, 5, end superscript, plus, 12, x,
juin [17]

Answer:

The width is: w(x)=4x^2

The length is l(x)=2x^2+3x+5

Step-by-step explanation:

The given rectangle has area given algebraically by the function:

a(x)=8x^5+12x^3+20x^2

The width of the rectangle is the greatest common factor of 8x^5,  12x^3 and 20x^2

That is the width is: w(x)=4x^2

We now divide the area by the width to obtain the length of the rectangle:

l(x)=\frac{8x^5+12x^3+20x^2}{4x^2}

This simplifies to:

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l(x)=2x^2+3x+5

5 0
4 years ago
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Answer:

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