Answer:
a: z = -1.936
b: 0.0265
d: z < -1.645
Reject H0 if z < -1.645
Step-by-step explanation:
We are given:
H0: µ = 20
HA: µ < 20
n = 60, sample mean: 19.6, σ = 1.6
Since the alternate hypothesis has a < sign in it, it is a left tailed test. The < or > sign in the alternate hypothesis points towards the rejection region.
For a: We need to calculate the test statistic for our situation. This is done with a z-score formula for samples.
For b: we need to use the z-score table to look up the p-value for the score we calculate in part a. The p-value is 0.0265. This means that there is only about a 2.65% chance that the sample values were a result of random chance.
For d: Since the significance level is 0.05, and this is a one tailed test, we have a critical value of z < - 1.645. This means that if the z-score we calculate in part a is less than -1.645, we will reject the null hypothesis
See attached photo for all the calculations!
Step-by-step explanation:
(1) 4mn × 6mp × 3mnp
= 4 × 6 × 3 ( mn × mp × mnp)
= 72 × (m³n²p²)
72m³n²p²
sorry, I'm busy, won't be able to complete it
2/1 = 14/x
cross mulitply
2x=14
2x/2=14/2
x=7
The width is 7 cm
Answer:
300 Backpacks each week]
Step-by-step explanation:
dont have an explanation srry but the answer is totally 300 backpacks a week