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natta225 [31]
2 years ago
11

Natalie has 500 candy bars to sell for a fundraiser. Let C be the number of candy bars. Let P be the amount made from selling th

e candy bars. Suppose that P equals 2 C minus 250 gives P as a function of C.
Identify the correct description and appropriate set of values for the domain of the function.



the number of candy bars; the set of all real numbers from 0 to 250


the number of candy bars; {0, 1, 2, 3, …, 500}


the amount made from selling the candy bars; {0, 1, 2, 3, …, 500}


the amount made from selling the candy bars; the set of all real numbers from 0 to 250
Mathematics
1 answer:
Contact [7]2 years ago
4 0

1. Writing p as a function of c gives

P =2c-250

Where C is the number of candy bar

P is the number of candy bar sold.

2. This is expressed as

0 =< C <= 250

3. This is expressed as

0 =< C =< 250

4. Amount made from selling candy bar in the set of interger between 0 to 500

C is given as 500

From the equation P=2C-250

P=2×500-250

P=1000-250 =750.

P=750

5. Amount made selling candy bar for the set of real numbers between 0 and 250

C is equal to 250

From the equation, we have

P=2×250-250

P=500-250 =250.

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9 months ago
Lou has an account with $10,000 which pays 6% interest compounded annually. If to that account, Lou deposits $5,000 at the begin
katovenus [111]

Answer:

Option d. $22154 is the right answer.

Step-by-step explanation:

To solve this question we will use the formula A=P(1+\frac{r}{n})^{nt}

In this formula A = amount after time t

                        P = principal amount

                        r = rate of interest

                       n = number of times interest gets compounded in a year

                        t = time

Now Lou has principal amount on the starting of first year = 10000+5000 = $15000

So for one year A=15000(1+\frac{\frac{6}{100}}{1})^{1\times1}

= 15000(1+.06)^{1}

= 15000(1.06) = $15900

After one year Lou added $5000 in this amount and we have to calculate the final amount he got

Now principal amount becomes $15900 + $ 5000 = $20900

Then putting the values again in the formula

A=20900(1+\frac{\frac{6}{100}}{1})^{1\times1}

= 20900(1+.06)^{1}

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So the final amount will be $22154.

3 0
2 years ago
Which values represent the first two terms of the sequence a1=2 and an=-2(an-1)^2?
Mars2501 [29]
Hello,

a_{1}=2
a_{n+1}=-2*a_{n}^2

a_{1}=2
a_{2}=-2*2^{2}=-8
a_{3}=-2*(-8)^{2}=-2*64=-128


Answer C






3 0
2 years ago
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