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Alisiya [41]
3 years ago
9

-3(-4n + 30) = -30 need help​

Mathematics
1 answer:
DIA [1.3K]3 years ago
6 0

First we will do -3 times everything in the parenthesis.

-3 times -4n = 12n

-3 times 30 = -90

SO,

12n - 90 = -30

       +90    +90

12n = 60

divide 12 on both sides;

n = 5

This is your answer,

IF THIS HELPED, PLS GIVE ME BRAINLIEST!

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1⁄2 × 1⁄5 =<br><br> help//.....
skad [1K]

Answer:

1/10

Step-by-step explanation:

1/2 * 1/5

Multiply the numerators

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Out of seniors at a local high school, 60% went on the senior trip. At the hotel , one room was reserved for every 4 students .
sweet [91]

Answer:

<u>Number of rooms reserved for the students are - 90 .</u>

Step-by-step explanation:

Firstly ,

As we know 60% of the 600 students went on the trip,

Then ,

Number of students went on the trip = 60% of 600

                                                          = \frac{60}{100}\times600

                                                        = 360

Now ,

Given - One room is reserved  for 4 students ,

Therefore , Number of rooms for 360 students = \frac{360}{4}

                                                                             = 90

<u>Hence , the answer is  90 rooms reserved for the students.</u>

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3 years ago
What is the upper quartile of the box plot graph?
julia-pushkina [17]
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3 0
3 years ago
The Highway Safety Department wants to study the driving habits of individuals. A sample of 32 cars traveling on the highway rev
GarryVolchara [31]

Answer:

n=126

Step-by-step explanation:

Data given and previous concepts

\bar X=60 represent the sample mean

s=11 represent the sample deviation

n=32 represent the sample size

Confidence =0.95 or 95%

\alpha =1-0.95=0.05 represent the significance level

ME= 2 represent the margin of error required

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

X \sim N(\mu, \sigma)

Solution to the problem

Since we don't have the population deviation. We know that the margin of error for a confidence interval is given by:

Me=t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The next step would be find the value of \t_{\alpha/2}, \alpha=1-0.95=0.05 and \alpha/2=0.025. The degrees of freedom are given by:

df=n-1=32-1=31

Using the normal standard table, excel or a calculator we see that:

t_{\alpha/2}=2.04

And the code in excel is this one:  "=T.INV(1-0.025,31)"

If we solve for n from formula (1) we got:

\sqrt{n}=\frac{t_{\alpha/2} s}{Me}

n=(\frac{t_{\alpha/2} s}{Me})^2

And we have everything to replace into the formula:

n=(\frac{2.04(11)}{2})^2 =125.88

And if we round up the answer we see that the value of n to ensure the margin of error required \pm=2 miles is n=126.

3 0
3 years ago
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