You can arrange them 16 times
1) aabb
2) aabb
3) bbaa
4) bbaa
5) abab
6) abab
7) abab
8) baba
9) baba
10) abba
11) baba
12) baab
13) baab
14) baab
15) baab
16) abba
To solve this problem you must apply a theorem called: Intersecting secant theorem. The proccedure is shown below:
1) For the figure shown on the left:
(5)(x+5)=(6)(4+6)
5x+25=60
5x=60-25
x=35/5
x=7
2) For the figure shown on the right:
(3)(3+5)=(4)(x+4)
24=4x+16
24-16=4x
8=4x
8/4=x
x=2
It's the last one. 15/2 is 7.5.
Therefore you must do the same to the 9. Divide 9 by 7.5 To give you 1.2 and that's your answer.
For this case we have to rewrite the given expression algebraically:
the cube of a, is represented as: 
the square of b, is represented as:
Thus, the product of both expressions is:
And twice the product is represented as:
Answer:
Answer:
17.5
Step-by-step explanation:
