All categories

2 years ago

What two numbers multiply to 14 and add up to -9?

Mathematics

2 answers:

photoshop1234 [79]2 years ago

5 0

Answer:

-7 and -2

Step-by-step explanation:

-7•-2=14

-7+(-2)=-9

Papessa [141]2 years ago

3 0

Answer:

-7 and -2

Step-by-step explanation:

-7 *-2=14

-7+-2=-9

calculate it and see obvi

You might be interested in

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

<u>ANSWER: </u>

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

<u>SOLUTION:</u>

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

2 years ago

I need help with Algebra. is this a good site?

forsale [732]

Answer:

Yes! I use this site all the time and my questions always get answered quickly!

Step-by-step explanation:

7 0

2 years ago

PLEASE HELP!!!! DUE TODAY

Tems11 [23]

Answer:

Step-by-step explanation:

$ 86,000 lies in the category $84201 - $ 160725

Tax = 14,382.50+ 24% of the amount over $84,200

Amount over $84,200= 86,000 - 84,200 = $1,800

Tax for the amount $ 1,800 =24% * 1800 = 0.24 * 1800

= $ 432

Tax for the amount $86,000 = 14382.50 + 432

=$ 14814.50

3 0

3 years ago

Which of these is NOT an integer

Tema [17]

Hi there!

»»————-　★　————-««

I believe your answer is:

Option A

»»————-　★　————-««

Here’s why:

⸻⸻⸻⸻

$\boxed{\text{Option A:}}\\\\3^{-5}\\\\\rightarrow \frac{1}{3^5}\\\\\rightarrow \frac{1}{243}\\\\\ \text{This is \textbf{NOT} an integer.}}$

⸻⸻⸻⸻

$\boxed{\text{Option B:}}\\\\-3^5\\\\\rightarrow -3 * -3 * -3 * -3 * -3 \\\\\rightarrow \boxed{-243}\\\\\\\text{This \textbf{IS} an integer.}$

⸻⸻⸻⸻

$\boxed{\text{Option C:}}\\\\\frac{1}{3}^{-5} \\\\\rightarrow \frac{1}{(\frac{1}{3})^5}\\\\\rightarrow \frac{1}{\frac{1}{243} }\\\\\rightarrow \boxed{243}\\\\\\\text{This \textbf{IS} an integer.}$