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3 years ago

What is an equation of the line that passes through the point (8,-7)(8,−7) and is parallel to the line 5x+4y=165x+4y=16?

Mathematics

1 answer:

Gnoma [55]3 years ago

6 0

Answer:

The equation of line parallel to given line passing through (8,-7) is:

$y = -\frac{5}{4}x+3$

Step-by-step explanation:

Given line is:

5x+4y=16

first of all, we have to convert the equation of given line in slope-intercept form

$4y = -5x+16$

Dividing both sides by 4

$\frac{4y}{4} = -\frac{5x}{4} + \frac{16}{4}\\y = -\frac{5}{4}x+4$

Slope intercept form is:

$y=mx+b$

The slope of given line is:

$m = -\frac{5}{4}$

Let m1 be the slope of line parallel to given line

"The slopes of two parallel lines are equal"

$m = m_1\\m_1 = -\frac{5}{4}$

The equation of line parallel to given line will be:

$y = m_1x+b$

Putting the value of slope

$y = -\frac{5}{4}x+b$

Putting the point (8,-7) in the equation

$-7 = -\frac{5}{4}(8)+b\\-7 = -(5)(2) + b\\-7 = -10+b\\b = -7 +10\\b = 3$

Putting the value of b

$y = -\frac{5}{4}x+3$

Hence,

The equation of line parallel to given line passing through (8,-7) is:

$y = -\frac{5}{4}x+3$

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3 years ago

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Answer:

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Step-by-step explanation:

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the step 1 is correct

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4 years ago

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Step-by-step explanation:

For an absolute value function, the graph will look like an arrow with a sharp inflection point.

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3 years ago

Read 2 more answers

Can someone please explain how to do these?

Pani-rosa [81]

Answer:

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For the first limit, plug in $x=8$ in the expression $(9x-3)$ , that's the answer for linear equations and limits.

So we have:

$9x-3\\9(8)-3\\72-3\\69$

The answer is 69

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$\frac{x^2+8x-9}{x^2-1}\\\frac{(x+9)(x-1)}{(x-1)(x+1)}\\\frac{x+9}{x+1}$

Now putting 1 in $x$ gives us the limit:

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So the answer is 5

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3 years ago