The true statement is (g•f)(x) = x ⇒ answer D
Step-by-step explanation:
Let us revise the relation between a function and its inverse
- The inverse of the function f(x) = y is g(y) = x
- The function and its inverse are reflections across the line y = x
- The graph of f(x) and the graph of its inverse g(x) are intersected at a point lie on the line y = x
- f(g(x)) = g(f(x)) = x
Example:
g(x) is the inverse function of f(x)
∵ f(x) = x - 5
∵ f(x) = y
∴ y = x - 5
To find the inverse switch x and y and find y
∵ x = y - 5
- Add 5 to both sides
∴ x + 5 = y
∴ g(x) = x + 5
Let us find f(g(x)) and g(f(x)0
To find f(g(x)) substitute x in f(x) by g(x)
∵ f(g(x)) = (x + 5) - 5
∴ f(g(x)) = x + 5 - 5
∴ f(g(x)) = x
To find g(f(x)) substitute x in g(x) by f(x)
∵ g(f(x)) = (x - 5) + 5
∴ g(f(x)) = x - 5 + 5
∴ g(f(x)) = x
Now let us solve the question
∵ f(x) and g(x) are inverse functions of each other
∴ f(g(x)) = g(f(x)) = x
The true statement is (g•f)(x) = x
Learn more:
You can learn more about the inverse function in brainly.com/question/2456302
#LearnwithBrainly
Answer:
<h2>Sorry I couldn't find it.</h2>
Step-by-step explanation:
<h3>:((((((((((((((((</h3>
Answer:
And we want to find the domain. And that represent the possible values for x. Since we have a quadratic function we have that the domain would be all the reals, and we can write:
![D= [x \in R]](https://tex.z-dn.net/?f=%20D%3D%20%5Bx%20%5Cin%20R%5D)
Where D represent the domain and R the set of the real numbers.
Step-by-step explanation:
For this case we have the following function:
And we want to find the domain. And that represent the possible values for x. Since we have a quadratic function we have that the domain would be all the reals, and we can write:
Where D represent the domain and R the set of the real numbers.
The question did not show the original vertices of A, B, and C.
Generally, for a triangle ABC that is dilated by a scale factor of four to form triangle A'B'C', the coordinates of vertices A', B', C' are:
For A(x, y)
The coordinate of vertex A' will be A' (4x, 4y)
For B(x, y)
The coordinate of vertex B' will be B' (4x, 4y)
For C(x, y)
The coordinate of vertec C' will be C' (4x, 4y)
![\bf tan(x^o)=1.11\impliedby \textit{taking }tan^{-1}\textit{ to both sides} \\\\\\ tan^{-1}[tan(x^o)]=tan^{-1}(1.11)\implies \measuredangle x=tan^{-1}(1.11)](https://tex.z-dn.net/?f=%5Cbf%20tan%28x%5Eo%29%3D1.11%5Cimpliedby%20%5Ctextit%7Btaking%20%7Dtan%5E%7B-1%7D%5Ctextit%7B%20to%20both%20sides%7D%0A%5C%5C%5C%5C%5C%5C%0Atan%5E%7B-1%7D%5Btan%28x%5Eo%29%5D%3Dtan%5E%7B-1%7D%281.11%29%5Cimplies%20%5Cmeasuredangle%20x%3Dtan%5E%7B-1%7D%281.11%29)
plug that in your calculator, make sure the calculator is in Degree mode
