The terms in which value of x when substituted leaves final value of p(x) = "0".
Here, x - 2 is factor. So value of x is 2.
Substituting value of x we get,
p(x) = x3 - 3x + 5a
p(2) = 2*3 - 3(2) + 5a
0+ 8-6 + 5a
-2 = 5a
a= -0.4
Plz mark me as brainliest
X=- 4/5
X=-0.8
That’s the answer to your problem to your question
Given:
- Bought n items of product A at 1/5 rs each
- bought n items of product B at 1/4 rs each
He mixed the two items and sold each at 2/9 rs each.
He lost 3 rs in the above batch of articles.
Solution:
revenue = 2n* (2/9) rs = 4n/9 rs
cost = n/5+n/4 rs = n(1/5+1/4)
Profit = revenue-cost = 4n/9-n(1/5+1/4) = -3 rs
Solve for n
4n/9-n(1/5+1/4) = -3
factor out n
n(4/9-1/5-1/4)=-3
n(80-36-45)/180=-3
-n/180=-3
n=3*180=540
Total number of products bought
= n+n = 540+540 = 1080
U^2(2u+3)+7(2u+3)
(u^2+7)(2u+3)
