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2 years ago

12

In a survey, each of 500 people was found to have a checking account, a savings account, or both. If 300 of these people have ch

ecking accounts and 300 have savings accounts, how many people have both a checking account and a savings account?

1 answer:

alukav5142 [94]2 years ago

6 0

Answer:

100

Step-by-step explanation:

300 + 300 = 600

600 - 500 = 100

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disa [49]

Answer: x

Step-by-step explanation:

6 0

2 years ago

11. Lucas is making one dozen sn

anygoal [31]

Answer:

Lucas needs 12 cups of dried cherries and 24 cups of dried apricots to make one dozen of snacks for his team

Step-by-step explanation:

For each snacks Lucas uses one cup of dried cherries and 2 cup of dried apricots. One dozen of snack contains a total of 12 snacks. Therefore to prepare 12 snacks (one dozen) the number of dried cherries and dried apricots can be gotten by multiplying the number of dried cherries and dried apricots required for each snack by 12.

Number of dried cherries = 1 cup for each snack × 12 snacks = 12 cups

Number of dried apricots = 2 cup for each snack × 12 snacks = 24 cups

Lucas needs 12 cups of dried cherries and 24 cups of dried apricots to make one dozen of snacks for his team

3 0

2 years ago

X < -10/3 or x > 2/3

Fittoniya [83]

Hello! :)

Here is a graph for x < -10/3 or x > 2/3.

THEDIPER

6 0

3 years ago

A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect

Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

<em>D</em> = a person has the disease

<em>X</em> = the test is positive.

The information provided is:

$P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99$

Compute the probability that a person does not have the disease as follows:

$P(D^{c})=1-P(D)=1-0.88=0.12$

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

$P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264$

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

$P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188$

Compute the probability that a randomly selected person is tested negative as follows:

$P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})$

$=0.0264+0.1188\\=0.1452$

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

4 0

2 years ago

Find the area of this triangle... Round to the nearest tenth and include units in your answer

alina1380 [7]

Answer:

36 m^2

Step-by-step explanation:

the formula for the area of a triangle is 1/2•b•h

so you’re going to do 1/2 times 12 times 6 to get the area of 36 m^2

4 0

2 years ago