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VashaNatasha [74]
3 years ago
9

Two guitars are in tune. They each play the same notes together. What would happen if one guitar slowly has its strings tightene

d? A) The harmonic sound will get lower in frequency. B) The sound gets larger due to constructive interference. C) The two sounds will refract and reach you at different times. D) Repeated louder and softer sounds will be heard due to varying interference.
Physics
1 answer:
Alenkasestr [34]3 years ago
8 0

D. repeated louder and softer sounds will be heard due to varying interference. Hope it helps :)

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If the volume of an object is reported as 5.0 ft3 what is the volume in cubic meters
12345 [234]
The problem statement is simply asking us to convert units. We convert from units of ft^3 to units of m^3. To do this, we need a conversion factor. For this case, we use 1 m is equal to 3.28084 ft. We do as follows:

5.0 ft^3 ( 1 m / 3.28084 ft )^3 = 0.1416 m^3
3 0
4 years ago
How long would it take to travel one light year?
Llana [10]
It depends on what speed you are going at. Assuming you are in our fastest spacecraft as of now which has a speed of 17,500 mph
1 light second = 186,282 mph
There are <span>31,536,000 in one year so 17,500x=31,534,000 and your answer would be in years. It would take you roughly 1802 years.</span>
(Sorry about mph I'm American.) 
5 0
3 years ago
How does evaporation happen on a stove<br> (dont mind the subject btw)
Shtirlitz [24]

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Answer: Evaporation happens by heat being transferred to the pot, then the pot transfering the heat to the water, which caused the water to vibrate more, eventually turning it into water vapor, which is how evaporation happens on the stove.

Explanation:

I hope this helped!

<!> Brainliest is appreciated! <!>

- Zack Slocum

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3 0
3 years ago
Read 2 more answers
Driving along a crowded freeway, you notice that it takes a time tt to go from one mile marker to the next. When you increase yo
ddd [48]

Answer:

38.6 mi/h

Explanation:

7.4 mi/h = 7.4mi/h * (1/60)hour/min * (1/60) min/s = 0.00206 mi/s

Let v (mi/s) be your original speed, then the time t it takes to go 1 mi/s is

t = 1/v

Since you increase v by 0.00206 mi/s, your time decreases by 15 s, this means

t - 15 = 1/(v+0.00206)

We can substitute t = 1/v to solve for v

\frac{1}{v} - 15 = \frac{1}{v + 0.00206}

We can multiply both sides of the equation with v(v+0.00206)

v+0.00206 - 15v(v+0.00206) = v

-15v^2 - 0.0308v + 0.00206 = 0

v= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

v= \frac{0.03083\pm \sqrt{(-0.03083)^2 - 4*(-15)*(0.00205)}}{2*(-15)}

v= \frac{0.03083\pm0.35}{-30}

v = -0.01278 or v = 0.01 0724 mi/s

Since v can only be positive we will pick v = 0.010724 mi/s or 0.010724*3600 = 38.6 mi/h

6 0
4 years ago
1) A particle move along the x axis, as x=tsquare-2t+1(SI unit). (a) The functions of its velocity and accelerator vector agains
Bond [772]

Answer:

\text{I believe this is calculus, no? But I believe that there should be a y-component of position}\\\text{But based off of the information provided, here goes:}\\\text{(a)}\\x'(t)=v(t)=\frac{d}{dt}t^2-2t+1\\v(t)=2t-2\text{ is the velocity vector}\\v'(t)=a(t)=\frac{d}{dt}2t-2\\a(t)=2 \text{ is the acceleration vector}\\\text{(b)}\\\text{Average Velocity }=\frac{x_{f}-x{i}}{t_{f}-t_{i}}\\=\frac{1-1}{2}=0, \text{based off of the information provided, the average velocity in the first 2 seconds}: 0m/s

8 0
3 years ago
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