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djverab [1.8K]
3 years ago
13

High values of Ksp greater than 1.0 infer: The solid phase is relatively insoluble. The solid phase is relatively soluble. The c

hemical reaction proceeds readily to the right. The chemical reaction proceeds readily to the left.
Physics
2 answers:
Anna71 [15]3 years ago
6 0

Answer:

Option The solid phase is relatively soluble.

Explanation:

The solubility constant of an ionic solid is given as an expression of the extent to which a substance can be soluble. The ratio is known as the solubility product constant and is given by the general expression:

K_{sp} = \frac{[products]}{[ reatants]}

where [ products] is the concentration of the products and [reactants] the concentration of the reactants.

A typical ionic reaction:

BaSO_{4}_{(s)} = Ba^{2+} _{(aq)} + SO_{4}^{2-} _{(aq)}

has the Ksp = [Ba²⁺][SO₄²⁻]

Nata [24]3 years ago
4 0

High values of Ksp greater than 1 infer that the solid phase is relatively soluble. The higher the Ksp value is, the greater the solid can be dissolve in the solution. It represents the level at which a solute dissolves in the solution.

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shepuryov [24]

Answer:

How big your foot is. (Big Brain)

Explanation:

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4 years ago
Object A of mass 0.70 kg travels horizontally on a frictionless surface at 20 m/s. It collides with object B, which is initially
AnnZ [28]

Answer:

25.71 kgm/s

Explanation:

Let K₁ and K₂ be the initial and final kinetic energies of object A and v₁ and v₂ its initial and final speeds.

Given that K₂ = 0.7K₁

1/2mv₂² = 0.7(1/2mv₁²)

v₂ = √0.7v₁ = √0.7 × 20 m/s = ±16.73 m/s

Since A rebounds, its velocity = -16.73 m/s and its momentum change, p₂ = mΔv = m(v₂ - v₁) = 0.7 kg (-16.73 - 20) m/s = 0.7( -36.73) = -25.71 kgm/s.

Th magnitude of object A's momentum change is thus 25.71 kgm/s

6 0
3 years ago
What factors will increase the amount of energy by kinetic
marissa [1.9K]

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Found this on cha-cha.com

4 0
3 years ago
A freight car of mass M contains a mass of sand m. At t = 0 a constant horizontal force F is applied in the direction of rolling
Veronika [31]

Answer:

Amount of linear movement

Explanation:

Our system is defined by the rate of change in mass that

leaves the car \Delta m_ {s} , this happens during a time interval

[t, t + \Delta t], in addition to freight car and sand at time t.

In this way we need to define the two states:

State 1,

consider t, m_ {c} (t) + \Delta m_ {s} and V.

State 2,

consider t + \Delta t, m_ {c} (t), V + V \Delta V

In this state is the mass of sand output, which

is composed of

\Delta m_{s}, V + \Delta V

In this way we define the Linear movement in x, like this:

p_ {x} (t) = (\Delta m_ {s} + m_ {c} (t)) v

p_ {x} (t+\Delta t) = (\Delta m_ {s} + m_ {c} (t)) (v + \Delta v)

m_ {c} (t) = m_ {c, 0} - bt = m_ {c} + m_ {s} -bt

In this way we proceed to obtain the Force

F =\lim_{\Delta t \rightarrow 0} \frac {p_x (t + \Delta t) -p_ {x} (t)} {\Delta t}

F = lim_{\Delta t \rightarrow 0} m_ {c} (t) \frac {\Delta v} {\Delta t} + lim_{\Delta t \rightarrow 0} m_ {s} (t) \frac {\Delta v} {\Delta T}

Since the mass of the second term becomes 0, the same term is eliminated, thus,

F = m_ {c} (t) \frac {dv} {dt}

\int\limit ^ {v (t)} _ {v = 0} dv = \int\limit^t_0 \frac{Fdt} {m_ {c} + m_ {s} -bt}

V (t) = - \frac {F} {b} ln (\frac {m_c + m_s-bt} {m_c + m_s})

3 0
3 years ago
How does energy transform from one form to another?
Sliva [168]
Energy can only be converted from one form to another

eg kinetic energy is converted to heat energy
4 0
3 years ago
Read 2 more answers
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