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4 years ago

If the volume of an object is reported as 5.0 ft3 what is the volume in cubic meters

1 answer:

3 0

The problem statement is simply asking us to convert units. We convert from units of ft^3 to units of m^3. To do this, we need a conversion factor. For this case, we use 1 m is equal to 3.28084 ft. We do as follows:

5.0 ft^3 ( 1 m / 3.28084 ft )^3 = 0.1416 m^3

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Which of the following is closest to 2cm?

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C because the the smallest thing then the other ones because it never said what kind of size of it

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Modern vehicles are designed ________ in a crash to absorb kinetic energy?

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Modern vehicles are designed to crush or crumple to absorb kinetic energy.

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3 years ago

If 20 beats are produced within a single second, which of the following frequencies could possibly be held by two sound waves tr

zhuklara [117]

The correct choice is

D. 22 Hz and 42 Hz.

In fact, the beat frequency is given by the difference between the frequencies of the two waves:

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D. 22 Hz and 42 Hz.

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3 years ago

Read 2 more answers

The 1st Law of Thermodynamics is a statement about (A) Temperatures scales (B) Whether a process can proceed in a specific manne

weqwewe [10]

Answer:

Energy conservation.

Explanation:

The 1st Law of Thermodynamics is a statement about energy conservation. It states that $\Delta U=Q-W$ , which means that if we substract the work W done by the system to the heat Q given to the system we get the change in the internal energy $\Delta U$ , so any excess in energy given to the system appears as internal energy, stating that energy is conserved.

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4 years ago

A 5.0-μC charge is placed at the 0 cm mark of a meter stick and a -4.0 μC charge is placed at the 50 cm mark. At what point on a

Maksim231197 [3]

Answer:

The distance from charge 5 μ C = 26.45 cm and the distance from - 4 μ C is 23.55 cm.

Explanation:

Given that

q₁ = 5 μ C

q₂ = - 4 μ C

The distance between charges = 50 cm

d= 50 cm

Lets take at distance x from the charge μ C ,the electrical field is zero.

That is why the distance from the charge - 4 μ C = 50 - x cm

We know that ,electric field is given as

$E=K\dfrac{q}{r^2}$

$K\dfrac{5\ \mu}{x^2}=K\dfrac{4\mu }{(50-x)^2}\\\\\dfrac{5}{x^2}=\dfrac{4 }{(50-x)^2}\\\\\\5(50-x)^2=4x^2\\(50-x)^2=0.8x^2\\\\50-x =0.89x\\\ x=\dfrac{50}{1.89}\ cm\\\\\\x=26.45\ cm\\$

Therefore the distance from charge 5 μ C = 26.45 cm and the distance from - 4 μ C is 23.55 cm.

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3 years ago