Subtract 5y ^ 2 - 6y - 11 from 6y ^ 2 + 2y + 5 .
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The standard form using integers of the equation is 6y - x = 42
<h3>How to determine the standard form</h3>Note that solving in standard form means writing it as a simple equation
Given y = 1/6x + 7
Find the LCM of the right side, we have
y =
Cross multiply
6 × y = x + 42
6y = x + 42
Make the variables move to the left side
6y - x = 42
Thus, the standard form using integers of the equation is 6y - x = 42
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