All categories

3 years ago

Please solve them I really need help

Mathematics

1 answer:

Ugo [173]3 years ago

8 0

Answer:

Answers are below

Step-by-step explanation:

12) No because the scale factor is not the same between the two rectangles

13) Yes. TUV is congruent to XYZ. The scale factor is 3/4.

14) Yes. I used SAS to see whether or not the triangles were similar. PQR is congruent to UVW.

15) Yes. I used 14) Yes. I used SAS to see whether or not the triangles were similar. DGH is congruent to FEH.

You might be interested in

find the surface are of a cylinder with a base diameter of 12 in and a height of 8 m use the value 3.14 for pi and do not do rou

alukav5142 [94]

Answer:

527.52 is your answer.

5 0

3 years ago

mary had 1 3/4 pound of blackberries. Mary's friend ate 3/4 of the blackberries. How many pounds of blackberries did Mary friend

OLEGan [10]

Hey there! I'm happy to help!

If Mary's friend at 3/4 of blackberries, we will simply multiply the total number of blackberries by 3/4 to find how many blackberries Mary ate.

3/4×1 3/4= 1 5/16

Therefore, Mary's friend at 1 5/16 pounds of blackberries.

I hope that this helps! Have a wonderful day!

3 0

3 years ago

BRAILIEST IF RIGHT Which other expression has the same value as (-14) - 8 ?

stiks02 [169]

Answer:

It's the last one (-14) +(-8)

Step-by-step explanation:

since (-14)-8 is -22 and the last one is also -22

4 0

3 years ago

Hey fellas, giving brainliest and a lot of points to who gets this correct

Ainat [17]

Answer:

$7\frac{1}{12}$ or $\frac{85}{12}$

Step-by-step explanation:

total boxes = Jills boxes + Mikes boxes

total boxes = $5\frac{1}{3} +1\frac{3}{4}$

= $\frac{16}{3} + \frac{7}{4}$

= $\frac{64+21}{12}$

= $\frac{85}{12}$

= $7\frac{1}{12}$

3 0

2 years ago

A marching band wants to line up for their performance. When they line up in threes there are 2 left over. When they line up in

aliina [53]

Answer:

59 students

Step-by-step explanation:

3s+2

5, 8, 11, 14, 17, 20, 23, 26, 29, 32, 35, 38, 41, 44, 47, 50, 53, 56, 59

4s+3

7, 11, 15, 19, 23, 27, 31, 35, 39, 43, 47, 51, 55, 59

5s+4

9, 14, 19, 24, 29, 34, 39, 44, 49, 54, 59

6s+5

11, 17, 23, 29, 35, 41, 47, 53, 59

The smallest number of students there could have been is 59.

4 0

3 years ago