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Zina [86]
3 years ago
5

Please solve them I really need help

Mathematics
1 answer:
Ugo [173]3 years ago
8 0

Answer:

Answers are below

Step-by-step explanation:

12) No because the scale factor is not the same between the two rectangles

13) Yes. TUV is congruent to XYZ. The scale factor is 3/4.

14) Yes. I used SAS to see whether or not the triangles were similar. PQR is congruent to UVW.

15) Yes. I used 14) Yes. I used SAS to see whether or not the triangles were similar. DGH is congruent to FEH.

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Anna11 [10]
First she would drive 165 miles.
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7 0
4 years ago
Someone please help.
Alexxandr [17]

Hi there!

f(x)+f(x+1)=4f(x)

There are 3 parts to this equation:

f(x)

f(x+1)

4f(x)

We must first determine these three parts separately.

<u>1) f(x)</u>

We're given that  f(x)=3^x:

⇒ f(x)=3^x:

<u>2) f(x+1)</u>

Now, we must find f(x+1). To do so, add 1 to x in the original function f(x)=3^x:

⇒ f(x+1)=3^x^+^1

<u>3) 4f(x)</u>

To find 4f(x), multiply the original function f(x)=3^x by 4:

4f(x)=4*3^x:

<u>4) Put it all together</u>

Now, plug each of the three parts into the equation f(x)+f(x+1)=4f(x):

f(x)+f(x+1)=4f(x)

3^x+3^x^+^1=4*3^x\\3^x+3^x*3=4*3^x

Factor the left side

3^x*(1+3)=4*3^x

Divide both sides by 3^x

1+3=4\\4=4

Because this equation is true, f(x)+f(x+1)=4f(x) is therefore true.

I hope this helps!

3 0
3 years ago
The area of a circle depends on the radius. Use the equation A(r) = (3.1415..)r^2 to compute A(6). Round your answer to the near
fredd [130]
Hello!

To solve this you put 6 in for r

When you put this into a calculator you get the answer of 113.10

Hope this helps!
3 0
3 years ago
I need help with #2. Can someone help me please?
shutvik [7]
11 pints because theres 6 pints in one gallon and that times two is 12 and that plus 3 and minus 6
8 0
3 years ago
Read 2 more answers
Whats 3/z = 2/5. Please HELP!! Due in 20 minutes!!!
attashe74 [19]

Step-by-step explanation:

Hey there!!

Given,

\frac{3}{z}  =  \frac{2}{5}

Cross multiply.

15 = 2z

Therefore, z= 15/2

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em>

3 0
3 years ago
Read 2 more answers
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