So subsitute
(4 times -16)/4=-64/4=-32/2=-16/1=-16
or
(4 times -16)/4=4/4 times -16/1=1 times -16=-16
answer is -16
Answer:
<h3>1</h3>
Step-by-step explanation:
The nth term of an exponential sequence is expressed as ar^n-1
The nth term of a linear sequence is expressed as Tn = a + (n-1)d
a is the first term
r is the common ratio
d is the common difference
n is the number of terms
Let the three consecutive terms of an exponential sequence be a/r, a and ar
second term of a linear sequence = a +d
third term of a linear sequence = a + 2d
sixth term of a linear sequence = a + 5d
Now if the three consecutive terms of an exponential sequence are the second third and sixth terms of a linear sequence, this is expressed as;
a/r = a + d ..... 1
a = a + 2d ..... 2
ar = a+ 5d .... 3
From 2: a = a + 2d
a-a= 2d
0 = 2d
d = 0/2
d = 0
Substitute d = 0 into equation 1:
From 1: a/r = a + d
a/r = a+0
a/r = a
Cross multiply
a = ar
a/a = r
1 = r
Rearrange
r = 1
<em>Hence the common ratio of the exponential sequence is 1</em>
Tell me if you have any questions or you need a step by step explanation
Answer:
Step-by-step explanation:
-1
The total of the 5 tests was 444, however the 6th test would have to be 96 in order to divide the 6 tests into a whole number 540 to get an average of 90
