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3 years ago

14

3/7 or 4/9 which is larger?

1 answer:

galben [10]3 years ago

6 0

Answer:

4/9

Step-by-step explanation:

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laiz [17]

Answer:

7

Step-by-step explanation:

2x² - 28x + 98 = 0

x² - 14x + 49 = 0

(x - 7)² = 0

x = 7

3 0

3 years ago

A puppy weighed 27 lb. His weight increased by 233% by the time he was 1 year old.

Ne4ueva [31]

1. you multiple 27 by 2.33 (which is the percent in the decimal form)
2. you add 27 to (27x2.33)
3. You should get about 89.91 pounds

4 0

3 years ago

Tyler says that an equivalent expression for 2^3 times 5^3 is 10^9. Is he correct? Explain.

Ipatiy [6.2K]

No, he is not correct. 2^3 = 8 and 5^3 = 125, so 8•125 = 1,000. 10^9 = 1,000,000,000.

6 0

3 years ago

How to do this ,I don’t understand

kondor19780726 [428]

Answer:

idk how to do this

Step-by-step explanation:

Sorry tho

6 0

3 years ago

Read 2 more answers

Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III

Paha777 [63]

Given:

$\sin x=-\dfrac{15}{17}$

x lies in the III quadrant.

To find:

The values of $\sin 2x, \cos 2x, \tan 2x$ .

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.

We know that,

$\sin^2 x+\cos^2 x=1$

$(-\dfrac{15}{17})^2+\cos^2 x=1$

$\cos^2 x=1-\dfrac{225}{289}$

$\cos x=\pm\sqrt{\dfrac{289-225}{289}}$

x lies in the III quadrant. So,

$\cos x=-\sqrt{\dfrac{64}{289}}$

$\cos x=-\dfrac{8}{17}$

Now,

$\sin 2x=2\sin x\cos x$

$\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})$

$\sin 2x=-\dfrac{240}{289}$

We know that,

$\cos 2x=1-2\sin^2x$

$\cos 2x=1-2(-\dfrac{15}{17})^2$

$\cos 2x=1-2(\dfrac{225}{289})$

$\cos 2x=\dfrac{289-450}{289}$

$\cos 2x=-\dfrac{161}{289}$

Using the trigonometric ratios, we get

$\tan 2x=\dfrac{\sin 2x}{\cos 2x}$

$\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}$

$\tan 2x=\dfrac{240}{161}$

Hence, the required values are $\sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}$ .

6 0

3 years ago