If 2 + 5i is a zero, then by the complex conjugate root theorem, we must have its conjugate as a zero to have a polynomial containing real coefficients. Therefore, the zeros are -3, 2 + 5i, and 2 - 5i. We have three zeros so this is a degree 3 polynomial (n = 3).
f(x) has the equation
f(x) = (x+3)(x - (2 + 5i))(x - (2 - 5i))
If we expand this polynomial out, we get the simplest standard form
f(x) = x^3-x^2+17x+87
Therefore the answer to this question is f(x) = x^3-x^2+17x+87
Answer: x=−3
Step-by-step explanation: Let's solve your equation step-by-step.
2
3
(3x+9)=−2(2x+6)
Step 1: Simplify both sides of the equation.
2
3
(3x+9)=−2(2x+6)
(
2
3
)(3x)+(
2
3
)(9)=(−2)(2x)+(−2)(6)(Distribute)
2x+6=−4x+−12
2x+6=−4x−12
Step 2: Add 4x to both sides.
2x+6+4x=−4x−12+4x
6x+6=−12
Step 3: Subtract 6 from both sides.
6x+6−6=−12−6
6x=−18
Step 4: Divide both sides by 6.
6x
6
=
−18
6
x=−3
D) median > mode... There is no mode and the median is 6...
Answer: B=16 and m=6
Step-by-step explanation:
in y=mx+b the number next to x is always the m/slope and the number without a variable is always the b.
