THIS IS THE COMPLETE QUESTION BELOW
The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.
Answer
$168.27
Step by step Explanation
Given p=90000/400+3x
With the limits of 40 to 50
Then we need the integral in the form below to find the average price
1/(g-d)∫ⁿₐf(x)dx
Where n= 40 and a= 50, then if we substitute p and the limits then we integrate
1/(50-40)∫⁵⁰₄₀(90000/400+3x)
1/10∫⁵⁰₄₀(90000/400+3x)
If we perform some factorization we have
90000/(10)(3)∫3dx/(400+3x)
3000[ln400+3x]₄₀⁵⁰
Then let substitute the upper and lower limits we have
3000[ln400+3(50)]-ln[400+3(40]
30000[ln550-ln520]
3000[6.3099×6.254]
3000[0.056]
=168.27
the average price p on the interval 40 ≤ x ≤ 50 is
=$168.27
Step-by-step explanation:
Given functions are:
h(x) is the product of g(x) and f(x)
Combining like terms
Hence,
Keywords: Functions, product
Learn more about functions at:
#LearnwithBrainly
Answer:
sorry iuuytffsa at tfyui0
Answer:
15 quarters, 10 nickels
Step-by-step explanation:
multiply the first equation by -0.25 and add the second equation to it
________________
has 10 nickels
has 15 quarters
10(.05) +15(0.25) = 0.5 + 3.75 = 4.25
Hope this helps
