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Alla [95]
1 year ago
8

You need to create a fenced off region of land for cattle to graze. The grazing area must be a total of 500 square feet, surroun

ded by a fence, and in the shape of a regular polygon. Within this grazing area, the length of the apothem must be 10 feet long. Part I. Find the total perimeter of the grazing area. Part II. If the cost of the fence is $7.95 per linear foot, how much will it cost to place a fence around the entire grazing area
Mathematics
1 answer:
liq [111]1 year ago
7 0

Using area of regular Polygon, the perimeter of the total grazing area of regular polygon is 100 feet and the cost to place a fence around the entire grazing area is $795.

According to the question,

You need to create a fenced off region of land for cattle to graze. The grazing area must be a total of 500 square feet, surrounded by a fence, and in the shape of a regular polygon.

Within this grazing area, the length of the apothem must be 10 feet long.

  • In part 1 we asked to find the total perimeter of the grazing area using below polygon formula

The formula of the area of regular polygon = ap/2  

Where a is apothem and p is the perimeter.  

500 = 10 x p/2  

1,000 = 10 x p  

100 = p

Hence the perimeter of regular polygon the total grazing area is 100 feet.  

  • In part 2, the cost of the fence is $7.95 per linear foot, how much will it cost to place a fence around the entire grazing area

Now cost of fencing 1 foot = $7.59  

So, cost of fencing 100 feet = 7.59 x 100 = 759

Hence, the cost to place a fence around the entire grazing area of polygon is $795.

Learn more about polygon here

brainly.com/question/13310667

#SPJ4

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julsineya [31]

Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.01}{2.58})^2}=16641  

And rounded up we have that n=16641

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

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Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

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The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.01 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

For this case we can use as estimator for the proportion \hat p =0.5, since we don't have any other previous info. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.01}{2.58})^2}=16641  

And rounded up we have that n=16641

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Step-by-step explanation:

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