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Alla [95]
1 year ago
8

You need to create a fenced off region of land for cattle to graze. The grazing area must be a total of 500 square feet, surroun

ded by a fence, and in the shape of a regular polygon. Within this grazing area, the length of the apothem must be 10 feet long. Part I. Find the total perimeter of the grazing area. Part II. If the cost of the fence is $7.95 per linear foot, how much will it cost to place a fence around the entire grazing area
Mathematics
1 answer:
liq [111]1 year ago
7 0

Using area of regular Polygon, the perimeter of the total grazing area of regular polygon is 100 feet and the cost to place a fence around the entire grazing area is $795.

According to the question,

You need to create a fenced off region of land for cattle to graze. The grazing area must be a total of 500 square feet, surrounded by a fence, and in the shape of a regular polygon.

Within this grazing area, the length of the apothem must be 10 feet long.

  • In part 1 we asked to find the total perimeter of the grazing area using below polygon formula

The formula of the area of regular polygon = ap/2  

Where a is apothem and p is the perimeter.  

500 = 10 x p/2  

1,000 = 10 x p  

100 = p

Hence the perimeter of regular polygon the total grazing area is 100 feet.  

  • In part 2, the cost of the fence is $7.95 per linear foot, how much will it cost to place a fence around the entire grazing area

Now cost of fencing 1 foot = $7.59  

So, cost of fencing 100 feet = 7.59 x 100 = 759

Hence, the cost to place a fence around the entire grazing area of polygon is $795.

Learn more about polygon here

brainly.com/question/13310667

#SPJ4

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5 0
3 years ago
The Corporate Lawyer, a magazine for corporate lawyers, reported that out of 200 firms with employee stock ownership plans, 150
tiny-mole [99]

Answer:

The 90% confidence interval for the population proportion of all such firms with this as the primary motivation is (69.96%, 80.04%).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

The Corporate Lawyer, a magazine for corporate lawyers, reported that out of 200 firms with employee stock ownership plans, 150 indicated that the primary reason for setting up the plan was tax related.

This means that n = 200, \pi = \frac{150}{200} = 0.75

90% confidence level

So \alpha = 0.1, z is the value of Z that has a p-value of 1 - \frac{0.}{2} = 0.975, so Z = 1.645.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.75 - 1.645\sqrt{\frac{0.75*0.25}{200}} = 0.6996

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.75 + 1.645\sqrt{\frac{0.75*0.25}{200}} = 0.8004

As percent:

0.6996*100% = 69.96%

0.8004*100% = 80.04%.

The 90% confidence interval for the population proportion of all such firms with this as the primary motivation is (69.96%, 80.04%).

6 0
3 years ago
Slope = 1, y-intercept = -4 ??
dalvyx [7]
Slope (m) = 1
Y-intercept (b) = -4

Formula: y = mx + b
To put it in the y=mx+b formula, you just have to plug it in so the answer would be...

y = 1x + -4

Hope that helped
8 0
3 years ago
Read 2 more answers
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1 1/2 - 1/4=? 

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1  1
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1 1/4 is the answer.
4 0
3 years ago
A fair sold a total of 3,300 tickets on friday and saturday. it sold 100 more on friday than on saturday.how many tickets did th
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On Saturday - x tickets
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7 0
3 years ago
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