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Elena L [17]
3 years ago
12

Need geometry help please

Mathematics
1 answer:
Tatiana [17]3 years ago
8 0

Answer:

I think C

Step-by-step explanation:

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Solve the Anti derivative.​
Alex Ar [27]

Answer:

\displaystyle \int {\frac{1}{9x^2+4}} \, dx = \frac{1}{6}arctan(\frac{3x}{2}) + C

General Formulas and Concepts:

<u>Algebra I</u>

  • Factoring

<u>Calculus</u>

Antiderivatives - integrals/Integration

Integration Constant C

U-Substitution

Integration Property [Multiplied Constant]:                                                                \displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx

Trig Integration:                                                                                                           \displaystyle \int {\frac{du}{a^2 + u^2}} = \frac{1}{a}arctan(\frac{u}{a}) + C

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle \int {\frac{1}{9x^2 + 4}} \, dx<u />

<u />

<u>Step 2: Integrate Pt. 1</u>

  1. [Integral] Factor fraction denominator:                                                         \displaystyle \int {\frac{1}{9(x^2 + \frac{4}{9})}} \, dx
  2. [Integral] Integration Property - Multiplied Constant:                                   \displaystyle \frac{1}{9} \int {\frac{1}{x^2 + \frac{4}{9}}} \, dx

<u>Step 3: Identify Variables</u>

<em>Set up u-substitution for the arctan trig integration.</em>

\displaystyle u = x \\ a = \frac{2}{3} \\ du = dx

<u>Step 4: Integrate Pt. 2</u>

  1. [Integral] Substitute u-du:                                                                               \displaystyle \frac{1}{9} \int {\frac{1}{u^2 + (\frac{2}{3})^2} \, du
  2. [Integral] Trig Integration:                                                                               \displaystyle \frac{1}{9}[\frac{1}{\frac{2}{3}}arctan(\frac{u}{\frac{2}{3}})] + C
  3. [Integral] Simplify:                                                                                           \displaystyle \frac{1}{9}[\frac{3}{2}arctan(\frac{3u}{2})] + C
  4. [integral] Multiply:                                                                                           \displaystyle \frac{1}{6}arctan(\frac{3u}{2}) + C
  5. [Integral] Back-Substitute:                                                                             \displaystyle \frac{1}{6}arctan(\frac{3x}{2}) + C

Topic: AP Calculus AB

Unit: Integrals - Arctrig

Book: College Calculus 10e

7 0
2 years ago
3a b2 b3 4b2 4 5a what is the answer
Otrada [13]
Is there a piece of paper that comes with the questions? Or do I just pick one? If there is a piece of paper attached, please add it to your question. Thank you!
7 0
3 years ago
Please solve this <br>Solve by completing the square. 4x2+8x−3=0
Greeley [361]

Step-by-step explanation:

4x2+8x−3=0

For this equation: a=4, b=8, c=-3

4x2+8x+−3=0

Step 1: Use quadratic formula with a=4, b=8, c=-3.

x=

−b±√b2−4ac

2a

x= −(8)±√(8)2−4(4)(−3)

2(4)

x= −8±√112

8  x=−1+

1 2 √7 or x=−1+

−1 2 √7

Answer:  x=−1+

1 2√7 or x=−1+

−1 2 √7

7 0
2 years ago
SOMEBODY PLEASE HELP ME WITH THIS!!!
inn [45]

g+312 = 200 is how the equation is written


3 0
3 years ago
Read 2 more answers
Can someone help me pls
creativ13 [48]

Answer:

69

Step-by-step explanation:

caculator

69 hahahahahahaha

5 0
3 years ago
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