Consider c as the cost of the widget so that our given equation is
c = 0.1w^2 + 20w
Take the derivate of the equation.
d/dt (c = 0.1w^2 + 20w)
dc/dt = 0.2w + 20
Given dc/dt = $16000 per month, the number of widgets would contain:
16000 = 0.2w + 20
-0.2w = 20 - 16000
-0.2w = -15980
w = 79900 widgets
Step-by-step explanation:
Use SOH-CAH-TOA.
Sine = Opposite / Hypotenuse
Cosine = Adjacent / Hypotenuse
Tangent = Opposite / Adjacent
You're given an angle, the adjacent side to that angle, and the hypotenuse. So use cosine.
Cosine = Adjacent / Hypotenuse
cos 37° = 48 / x
Multiply both sides by x.
x cos 37° = 48
Divide both sides by cos 37°.
x = 48 / cos 37°
If desired, use a calculator to evaluate.
x ≈ 60.1
The correct answer is C
Sigma Notation is when we take all of the whole numbers between the starting point (which can be found as the number under the sigma sign) and the end number (which can be found above the sigma sign). Therefore, we will add together all of the values of 3k + 2 for when k is equal to all of the numbers between 2 and 7. So, let's evaluate each one first.
When k = 2
3(2) + 2 = 8
When k = 3
3(3) + 2 = 11
When k = 4
3(4) + 2 = 14
When k = 5
3(5) + 2 = 17
When k = 6
3(6) + 2 = 20
When k = 7
3(7) + 2 = 23
So we know we have the following.
8 + 11 + 14 + 17 + 20 + 23
Now for the number after the comma, we are just looking for the answer of them all added together. So the final answer should be
8 + 11 + 14 + 17 + 20 + 23, 93
Necesit. la versión en español plz 9
