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Mazyrski [523]
3 years ago
15

A function LaTeX: f\left(x\right)=3^xf ( x ) = 3 x is transformed into the function LaTeX: g\left(x\right)=-3^{x+4}-7g ( x ) = −

3 x + 4 − 7.
Choose the transformations that occurred. Choose all that apply.

Group of answer choices

Horizontal Shift Left

Vertical Shift Up

X-axis Reflection

Vertical Stretch

Vertical Compression

Horizontal Shift Right

Vertical Shift Down
Mathematics
1 answer:
Sveta_85 [38]3 years ago
6 0

Answer:

Vertical Shift Down, Horizontal Shift Left, X-axis Reflection.

Step-by-step explanation:

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Find the percent of change between the two numbers 2 and 1.42.
aleksley [76]

Answer:

29%

Step-by-step explanation:

\frac{0.58}{2}  \times 100 \\

29%

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Which best describes the triangle or the triangles, if any, that can be formed with two sides that measure 5 inches and an angle
Arte-miy333 [17]
One isosceles triangle
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Dara has to solve 35 math problems for homework. She has completed 14 of them. What fraction of the problems does she have left
oksian1 [2.3K]

Answer:

The answer is 21/35 or 3/5

Step-by-step explanation:

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6 0
2 years ago
two telephone calls come into a switchboard at times that are uniformly distributed in a fixed one-hour period. assume that the
AleksandrR [38]

We wil assume a variable x to be the total number of calls received by the switchboard.

The question also says to assume that the calls were made independently.

Given:

Calls are independent.

Calls are uniformly distributed over a 1 hour period.

Ans (a). The calls are distributed uniformly over 1 hour, hence: (0, 1).

So we have,

f1(x1) = 1

f2(x2) = 1

X1 and X2 are considered to be independent of each other. Hence,

f(x1,x2) = f1 (x1) f2 (x2)

f(x1,x2) = 1 (1)

f(x1,x2) = 1

Thus,

P(X1 <= 0.5; X2 <= 0.5) = ∫0.50 ∫0.50 f(x1,x2) dx2 dx1

= ∫^0.5 0 ∫^0.5 0 (1) dx2 dx1

= ∫^0.5 0 (x2^0.5 0) dx1

= ∫^0.5 0 (0.5 - 0) dx1

= 0.5 ∫^0.5 0 dx1

= 0.5 (x1^0.5 0)

= 0.5 (0.5 - 0)

= 0.25

Therefore, the probability that the calls were received within the first 30 minutes or first half hour is 0.25.

Ans (b). Steps 1 and 2 are the same as the above answer.

Probability = [∫^11/12 0 ∫^x1 + 1/12 x1 1dx2 dx1] + [∫^1 1/12 ∫^x1 x1-1/12 1dx2 dx1

= [∫^11/12 0 (x2 ^x1+1/12 x1 dx1] + [∫^1 1/12 (x2 ^x1 x1-1/12 dx1)]

= [∫^11/12 0 (x1 + 1/12 -x1) dx1] + [∫^1 1/12 (x1 - x1 + 1/12) dx1]

= [(1 + x1/12 - 1) ^11/12 0] + [( 1 - 1 + x1/12) ^1 1/12]

= 11/144 + 11/144

= 0.1528

Therefore, the probability that the calls were received within five minutes of each other is 0.15.

Find more from: brainly.com/question/18125359?referrer=searchResults

#SPJ4

7 0
10 months ago
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