Ok so for part A, the x-coordinate of the intersection is the solution to <span><span>2<span>−x</span></span>=<span>4<span>x+3.
Part B </span></span></span><span>y>3x+10</span> for (8,10)
<span><span><span>10>3(8)+10</span><span>10>34
I am not sure about the thrid one
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Answer:
It goes into 100356 290 times with a remainder of 16
Step-by-step explanation:
100356/346 = 290 R 16
Answer:
y = (x+3)² - 1
Step-by-step explanation:
To complete the square take the middle term b and divide by 2. Then square the value.
Here b = 6.
So 6/2 = 3
3² = 9
Add 9 to both sides of the equation.
x² + 6x + 8 = 0
x² + 6x + 9 + 8 = 9
(x+3)² - 1 = y
Answer:
-t = -8 ×5
-t = -40
t= 40
good luck have a nice day
The point A is located in quadrant II
The coordinate of the origin is always (0,0)
