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Lisa [10]
3 years ago
7

What is the value of y?

Mathematics
2 answers:
klio [65]3 years ago
8 0
It is the y axis of a origin
Sati [7]3 years ago
4 0
I need more information for this, the y-axis!
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Can u help me do this
chubhunter [2.5K]
There will be 2 books left over if he fills each box.
7 · 4 = 28
30 - 28 = 2

Good Luck
5 0
3 years ago
Which expression has the same value as Negative 18 divided by (negative 9)?
Mandarinka [93]

Answer:

The answer is 36/18.

Hope this helps.

5 0
3 years ago
Read 2 more answers
Can someone help me pls
FrozenT [24]
There are 4 lateral faces that are triangles.  Each triangle is: A = \frac{b  x  h}{2}
A = \frac{16  x  22}{2}
   = 176

There is one base that is a square. A = L x W
A = 16 x 16
   =  256

Surface area = 256 + 4(176)
                     =  256 + 704
                     = 960

Answer: B

8 0
3 years ago
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the hypotenuse of a 30-60-90 degree right triangle has a measure of 10. what is the measure of the shortest side
VARVARA [1.3K]

Answer:

5

Step-by-step explanation:

A 30-60-90 triangle's sides equal as follows:

Hypotanuse= x (a number)

Long side= x/2( also can be calculated as x* 1/2) * \sqrt{3}

Short side = x/2 or x * 1/2

5 0
3 years ago
The harbormaster wants to place buoys where the river bottom is 20 feet below the surface of the water. Complete the absolute va
Natalija [7]

Answer:

The answer is below

Step-by-step explanation:

The bottom of a river makes a V-shape that can be modeled with the absolute value function, d(h) = ⅕ ⎜h − 240⎟ − 48, where d is the depth of the river bottom (in feet) and h is the horizontal distance to the left-hand shore (in feet). A ship risks running aground if the bottom of its keel (its lowest point under the water) reaches down to the river bottom. Suppose you are the harbormaster and you want to place buoys where the river bottom is 20 feet below the surface. Complete the absolute value equation to find the horizontal distance from the left shore at which the buoys should be placed

Answer:

To solve the problem, the depth of the water would be equated to the position of the river bottom.

d(h)=river \ bottom\\\\The \ river \ bottom=-20\ feet(below)\\\\d(h) = -20\\\\\frac{1}{5}|h-240|-48=-20\\ \\\frac{1}{5}|h-240|=-20+48\\\\\frac{1}{5}|h-240|=28\\\\|h-240|=28*5\\\\|h-240|=140\\\\h-240=140\ or\ h-240=-140\\\\h=140+240\ or\ h=-140+240\\\\h=380\ or\ h=100\\\\The\ buoys\ should\ be\ placed\ at\ 100\ feet\ and\ 380\ feet\ from\ left-hand\ shore

4 0
4 years ago
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