an average ant is 1/4 of an inch long. an average aphid is 3/32 of an inch long. how many times longer is the ant than the aphid

1 answer:

3 0

First find the common denominator. In this case, you would want to use 32. So, 1/4 = 8/32. So, an ant is 8/32 of an inch and an aphid is 3/32 of an inch. Now to find the difference, you subract. 8/32 - 3/32 = 5/32. So the answer is, the ant is 5/32 of an inch longer.

You might be interested in

Question:<br>30% of $40 is $<br>

snow_lady [41]

Answer:

28.00

Step-by-step explanation:

You can also calculate how much you save by simply moving the period in 30.00 percent two spaces to the left, and then multiply the result by $40 as follows: $40 x . 30 = $12.00 savings.

Hope it helped

7 0

3 years ago

If the balance at the end of eight years on an investment of $630 that has been invested at a rate of 9% is $1,083.60, how much

Contact [7]

The interest is $453.60.

The total amount includes principal + interest. The principal was 630 and the total amount was 1083.60.
1083.60 - 630 = 453.60.

3 0

3 years ago

A boat leaves a dock and travels 9 miles due north and 12 miles due west. Find how far the boat is from the dock. Type the corre

adelina 88 [10]

Answer:

15 miles

Step-by-step explanation:

Let's say the dock is at the origin on a coordinate plane and each unit is 1 mile. If the boat travels 9 mile due north, that means that we move up from the origin (0, 0) 9 units to point A (0, 9). Now, this boat moves 12 miles due west, so we will go 12 units to the left of (0, 9) to point B (-12, 9). See the attached drawing (sorry for the crudeness).

Notice that this is a right triangle with legs of 9 and 12. That means the distance from the boat to the dock is just the hypotenuse, so use the Pythagorean Theorem: distance = $\sqrt{9^2+12^2} =\sqrt{81+144} =\sqrt{225} =15$