Let
b-----------> the length side of the square box
h------------> the height of the box
SA---------> surface area of the box
we know that
[volume of the box]=b²*h
volume=256 in³
b²*h=256-------> h=256/b²-----> equation 1
surface area of the box=area of the base+perimeter of base*height
area of the base=b²
perimeter of the base=4*b
surface area=b²+(4*b)*h------> SA=b²+4*b*h-----> equation 2
substitute equation 1 in equation 2
SA=b²+4*b*[256/b²]-----> SA=b²+1024/b-----> SA=(b³+1024)/b
the answer is
the formula of the volume of the box is V=b²*h-----> 256=b²*h
the formula of the surface area of the box are
SA=b²+4*b*h
SA=(b³+1024)/b
Answer:
do not know what the question is but the equation for this would be
y=2100-51x
Answer:
where is the graph, I don't see, but I want to help
Answer:
V = 125.6 in³
Step-by-step explanation:
let V be volume, h the height and r the radius, then the equation relating the quantities is
V = khr² ← k is the constant of variation
To find k use the condition V = 402.12, h = 8, r = 4
402.12 = k × 8 × 4² = 128k ( divide both sides by 128 )
3.14 = k [ note 3.14 is π )
V = 3.14hr² ← equation of variation [ V = πr²h ]
Given r = 2 and h = 10, then
V = 3.14 × 10 × 2² = 3.14 × 40 = 125.6
